The question is an annuity question with the present value of the annuity given.
The
present value of an annuity is given by PV = P(1 - (1 + r/t)^-nt) /
(r/t) where PV = $61,600; r = interest rate = 9.84% = 0.0984; t = number
of payments in a year = 6; n = number of years = 11 years and P is the
periodic payment.
61600 = P(1 - (1 + 0.0984/6)^-(11 x 6)) / (0.0984 / 6)
61600 = P(1 - (1 + 0.0164)^-66) / 0.0164
61600 x 0.0164 = P(1 - (1.0164)^-66)
1010.24 = P(1 - 0.341769) = 0.658231P
P = 1010.24 / 0.658231 = 1534.78
Thus, Niki pays $1,534.78 every two months for eleven years.
The total payment made by Niki = 11 x 6 x 1,534.78 = $101,295.48
Therefore, interest paid by Niki = $101,295.48 - $61,600 = $39,695.48
Answer:
(rounded)17.2=Q
Step-by-step explanation:
Q= 13/cos41
Answer:
x= 7
Step-by-step explanation:
1st step: Multiply the factor (outside number) with the numbers and variable(s) in the box. This results in 2(x-3) = 2x-6
2nd Step: continue the rest of the equation since there are no more brackets left so 2x-6-12=-4
3rd Step: send -12 to the other side of the equation (side changes sign changes) so it will become 2x-6=-4+12 (You are actually supposed to make the variable alone on one side of the equation so that you would be able to calculate its value)
4th step: 2x-6=8 ---> send -6 to the other side as well which will then result in 2x=14
5th step: since 2 is being multiplied by x, when you send it to the other side (to make x alone) you will divide 14 by 2 ( sign of 2 changes from multiplication to division)
Final Step: x=7
Answer:
5 units
Step-by-step explanation:
According to the given statement Δ XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z' which means that each point in ΔXYZ is moved 4 units up and moved 3 units left.
To find the distance of each corresponding point we will use the Pythagorean theorem which states that the square of the length of the Pythagorean of a right triangle is equal to the sum of the squares of the length of other legs
The square of the required distance = 4^2+3^2 = 16+9 =25
By taking root of 25 we get:
√25 = 5
Thus, we can conclude that the the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ is 5 units.
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