Find the value of x. Please help

Item 5 Multiply. (−3.2)⋅1.7 −5.44 −1.5 1.5 5.44

Mekhanik [1.2K]

Answer:

-5.44 is the answer. You multiply the figures

8 0

3 years ago

Read 2 more answers

When planting a garden, 17 out of 25 plants sprout on time.

iogann1982 [59]

Answer:

8/25 or 32%

Step-by-step explanation:

if 17/25 do sprout on time than 8 or the twenty five don't. So 8/25 is the amount that don't and by multiplying both the top and bottom fraction by 4 you will get 32/100 or 32%

4 0

3 years ago

As part of a study on pulse rates, a random sample of 10 study participants had their pulse rate taken and asked to sit quietly

Ivahew [28]

Answer:

$t = \frac{-1.2-0}{\frac{2.97}{\sqrt{10}}}= -1.278$

The degrees of freedom are :

$df=n-1=10-1=9$

$p_v =2*P(t_{9}$

Since the p value is a very high value is higher than the typical values for the significance level (0.05,0.1) so then we have enough evidence to FAIL to reject the null hypothesis and there is no enough evidence to conclude that the true difference in the means is different from 0. And the best conclusion would be:

d. There is not enough evidence to conclude the mean difference in pulse rates before and after the 5 minute waiting period is different from 0.

Step-by-step explanation:

We are interested to check if the true difference in pulse rates before and after after 5 minute waiting period is 0 or no so then the system of hypothesis are:

Null hypothesis: $\mu_d =0$

Alternative hypothesis: $\mu_d \neq 0$

We have the following data given:

$\bar X_d = -1.2$ sample mean for the difference

$n =10$ the sample size

$s_d = 2.97$ sample standard deviation

The statistic is given by:

$t= \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

And replacing we got:

$t = \frac{-1.2-0}{\frac{2.97}{\sqrt{10}}}= -1.278$

The degrees of freedom are :

$df=n-1=10-1=9$

Since we are conducting a bilateral test te p value would be given by:

$p_v =2*P(t_{9}$

Since the p value is a very high value is higher than the typical values for the significance level (0.05,0.1) so then we have enough evidence to FAIL to reject the null hypothesis and there is no enough evidence to conclude that the true difference in the means is different from 0. And the best conclusion would be:

d. There is not enough evidence to conclude the mean difference in pulse rates before and after the 5 minute waiting period is different from 0.

7 0

4 years ago

What values of $x$ satisfy $|x - 4| + |x + 4| \leq 10$? express your answer in interval notation?

Diano4ka-milaya [45]

The answer is that x ∈ [-5,5]

7 0

3 years ago

K(n)=2n-2. find k(-4)

zlopas [31]

-10 is the answer
Plug in -4 for n so 2x-4-2=-10

4 0

3 years ago