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2 years ago

I don't understand how to find the negative. Some of these are wrong and just need help finding my errors

Mathematics

1 answer:

masha68 [24]2 years ago

5 0

Answer:

-5pi/4

Step-by-step explanation:

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A toy store wants to give away free goody bags to their customers. They have 60 lollipops and 72 stickers to give away. They wan

Flura [38]

60 because each bag has to be the same

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3 years ago

What is the slope intercept from two points <br><br> (1,4)and(2,2)<br><br> Y=______

vodomira [7]

<h2>Answer: Y= -2</h2>

Step-by-step explanation: use the formula y2-y2/x2-x1

3 0

2 years ago

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Which of the above polynomials is a 5th degree trinomial?

diamong [38]

Easy

5th degree means highest power is 5 so must have x^5

trinomial means 3 terms

A. trinomial, highes power is 5, check
b. trinomial, highest power is 3, nope
c. not a trinomial, highest power is 3, nope
d. not a trinoial, highest power is 5, nope

answer is A

7 0

3 years ago

Unsure how to do this calculus, the book isn't explaining it well. Thanks

krok68 [10]

One way to capture the domain of integration is with the set

$D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}$

Then we can write the double integral as the iterated integral

$\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx$

Compute the integral with respect to $y$ .

$\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)$

Compute the remaining integral.

$\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}$

We could also swap the order of integration variables by writing

$D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}$

and

$\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy$

and this would have led to the same result.

$\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)$

$\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)$

7 0

1 year ago

NEED HELP ASAP!!!!! PLEASE HELP ME

mina [271]

ANSWER

X = -9

EXPLANATION: you subtract 180 - 70 giving you 110

Equation set up: x + 49 + x + 79 = 110

7 0

3 years ago

Read 2 more answers