When two parallel lines are intersected by a transversal, the same-side exterior angles are supplementary. That means that their sum is 180.
Using that logic, if the two roads were parallel, then the sum of their same-side exterior angles will add up to 180. Yet their same-side exterior angles add up to 170 (130 + 40 = 170), hence they can't be parallel.
See the drawing attached below.
Using supplmenatry angles (two angles whose sum of measures add up to 180 or a straight line), we can say that:
m<DIE + m<HID = 18
40 + m<HID = 180
m<HID = 140
Similarly:
m<BHC + m<CHI = 180
130 + m<CHI = 180
m<CHI = 50
Using verticle angles therome, (when two lines intersect, the angles opposite to eachother are congruent, or have the same measure), we can say that:
m<DIE = m<GIH = 40
m<GIE = m<HID = 140
m<CHI = m<AHB = 50
m<BHC = m<AHI = 130
Answer:
first side=40
second side=20
third side=22
Step-by-step explanation:
LET THE SIDES OF THE TRIANGLES BE y
Perimeter=82
first side=2 x y = 2y
second side=y
third side=2 +y
2y + y + 2 + y=82
4y+2=82
4y= 82-2
4y=80
y=80/4
y=20
first side=2y=2(20)=40
second side=y=20
third side= 2 + y= 2 + 20 = 22
Answer:
none of the above the 7^8/8 is equivalent to
Let the length equal x
Then the width would be 4x + 8 (8 feet more than 4 times the length)
Area = length x width:
5,472 = x * 4x+ 8
Simplify:
5472 = 4x^2 + 8x
Subtract 5472 from both sides:
4 x^2 + 8x - 5472 = 0
Use the quadratic formula to solve for x.
X = 36
Now you know the length is 36 feet
The width = 4(36) + 8 = 152 feet
Now find the perimeter: 152 + 152 + 36 + 36 = 376 feet.
The answer is B. 376
The answer is (-1,1)
The solution is the point where the two lines cross each other
Hope this helps