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2 years ago

How are slope and speed related?

Mathematics

2 answers:

user100 [1]2 years ago

8 0

Answer:

The joint dependence of locomotive power on speed and slope is crucial in the non-stationary conditions where the skier passes high and low points along the track where both speed and slope change rapidly.

Step-by-step explanation:

Hope this helps you and also when your going down a slope there is movement which in this case you will pick up speed. If your trying to go up a slope your not going to move as fast rather slow.

Vinvika [58]2 years ago

3 0

Answer:

you will get speed on a slope and you will get speed with speed (:

Step-by-step explanation:

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Find the probability on #4 Please

julia-pushkina [17]

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3 years ago

What is extraneous roots?

kobusy [5.1K]

extraneous root is a solution o an equation that seems to be right but when we check it (by substituting it into the original equation) it turns out not to be right

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2 years ago

Solve this inequality. 7x + 2 > 30 A.x 224 B.x > 196 C.x 4 D.x > 3

Oliga [24]

Answer:

x > 4

Step-by-step explanation:

7x + 2 > 30

Subtract 2 from each side

7x + 2-2 > 30-2

7x > 28

Divide each side by 7

7x/7 > 28/7

x > 4

6 0

2 years ago

Read 2 more answers

If f(1) = 10 and f '(x) ≥ 3 for 1 ≤ x ≤ 6, how small can f(6) possibly be?

Natalka [10]

Answer:

$f'( x ) = \frac{f(b) - f(a)}{b - a} \\ = \frac{f(6) -f(a)}{6 - 1} \\ 3\leqslant \frac{f(6) - 10}{5} \\ 15\leqslant f(6) - 10 \\ f(6) \geqslant 15 + 10 \\ f(6) \geqslant 25$

6 0

2 years ago

Read 2 more answers

Solve the following pair of equations simultaneously.

Alchen [17]

Answer:

No solutions.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Solving systems of equations using substitution/elimination
Solving systems of equations by graphing
Expanding
Finding roots of a quadratic
Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define systems

2x - y = 9

4x² + 3y² - 2x + y = 16

Step 2: Rewrite systems

2x - y = 9

Subtract 2x on both sides: -y = 9 - 2x
Divide -1 on both sides: y = 2x - 9

Step 3: Redefine systems

y = 2x - 9

4x² + 3y² - 2x + y = 16

Step 4: Solve for x

Substitution

Substitute in y: 4x² + 3(2x - 9)² - 2x + (2x - 9) = 16
Expand: 4x² + 3(4x² - 36x + 81) - 2x + (2x - 9) = 16
Distribute 3: 4x² + 12x² - 108x + 243 - 2x + 2x - 9 = 16
Combine like terms: 16x² - 108x + 234 = 16
Factor GCF: 2(8x² - 54x + 117) = 16
Divide 2 on both sides: 8x² - 54x + 117 = 8
Subtract 8 on both sides: 8x² - 54x + 109 = 0
Define variables: a = 8, b = -54, c = 109
Resubstitute: $x=\frac{54\pm\sqrt{(-54)^2-4(8)(109)} }{2(8)}$
Exponents: $x=\frac{54\pm\sqrt{2916-4(8)(109)} }{2(8)}$
Multiply: $x=\frac{54\pm\sqrt{2916-3488} }{16}$
Subtract: $x=\frac{54\pm\sqrt{-572} }{16}$

Here we see that we start to delve into imaginary roots. Since on a real number plane, we do not have imaginary roots, there would be no solution to the systems of equations.

Step 5: Graph systems

We can verify our results.

8 0

2 years ago

How are slope and speed related?​

How are slope and speed related?