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Andrew [12]
3 years ago
12

Please help, very confused!

Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0
\bf cot(\theta)=\cfrac{1}{tan(\theta)}
\qquad \qquad 
csc(\theta)=\cfrac{1}{sin(\theta)}\qquad \qquad sin(-\theta )=-sin(\theta )
\\\\\\
\textit{also recall }sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta)\\\\
-------------------------------

\bf \cfrac{csc^2(x)-cot^2(x)}{sin(-x)cot(x)}\implies \cfrac{\frac{1}{sin^2(x)}-\frac{cos^2(x)}{sin^2(x)}}{-sin(x)\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{1-cos^2(x)}{sin^2(x)}}{-cos(x)}
\\\\\\
\cfrac{\frac{sin^2(x)}{sin^2(x)}}{-cos(x)}\implies \cfrac{1}{-cos(x)}\implies -sec(x)
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Step-by-step explanation:

    We need to write, or decide on, the equation for the blue line as this line represents the trend line for this scatter plot. We will write this in slope-intercept form. <em>See attached for a visual</em>.

    First, we will find our slope. We will use \frac{rise}{run} for this since we have a graph with clear points. See attached, we count up [5] and then count to the right [1] for a slope of 5.

     -> Slope = 5

   Now, we will find our y-intercept. This is where the line intersects the y-axis. The line hits the y-axis at point (0, 5) giving us a y-intercept of 5.

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   Lastly, we will write our equation and decide on an answer.

y = <em>m</em>x + <em>b</em>

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