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3 years ago

A lake was stocked with 380 trout.Each Year the population decreased by 19

Mathematics

1 answer:

AysviL [449]3 years ago

6 0

If I could help I would but I don’t understand how to do it

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Help, asap lol I forgot what it was and didn't take notes. <br>problem in photo attached ^.^

alex41 [277]

Answer:

Identity property of division

Step-by-step explanation:

3 0

3 years ago

If a cow takes 15 poops a day, and there is 10 cows, how many piles of poop are there in a day.

Thepotemich [5.8K]

Answer:

150 i think lol

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

If seven out of every thirteen trick-or-treaters that came to your house last Halloween were dressed as Buzz Lightyear, what pro

Zarrin [17]

6 is correct

if not let me know

7 0

3 years ago

Read 2 more answers

a real estate agent earns a commission of 4% of the selling price for each house he sells. How expensive of a house does he have

Vika [28.1K]

Given that rate of commission earned by the real estate agent = 4%

Given that required commission that real estate agents wants to earn = $7000.

Now we have to find about how expensive of a house does he have to sell to earn $7000.

So let the cost of house = $x

then commission earned = 4% of x

Given commision is $7000 so both quantities will be equal and we get equation:

4% of x = 7000

0.04x = 7000

x = 7000/0.04

x = 175000

Hence final answer is $175000.

8 0

3 years ago

The graph plots four equations, A, B, C, and D: Line A joins ordered pair negative 6, 16 and 9, negative 4. Line B joins ordered

Margaret [11]

Answer:

The pair of equations which has (2,12) as its solution is,

equation B and equation C.

Step-by-step explanation:

According to the question,

equation of line A is $\frac {y - 16}{x + 6} = \frac {16 + 4}{-6 - 9}$

or, $\frac {y - 16}{x + 6} = \frac {-4}{3}$

or, $3y - 48 = -4x - 24$

or, 3y + 4x = 24 ------------------(1)

Now, the point (2, 12) doesn't satisfy (1). Hence, (2,12) is not a solution for the line A.

Equation of line B is, $\frac {y - 20}{x + 2} = \frac {20 - 0}{-2 - 8}$

or, $\frac {y - 20}{x + 2} = -2$

or, $y - 20 = -2x - 4$

or, y + 2x = 16 -----------------------------(2)

The point (2,12) is satisfied by (2). Hence, (2, 12) is a solution for line B.

Equation of line C is, $\frac {y + 6}{x + 7} = \frac {20 + 6}{6 + 7}$

or, $\frac {y + 6}{x + 7} = 2$

or, y + 6 = 2x + 14

or. y - 2x = 8 -----------------------------------(3)

The point (2, 12) is satisfied by (3). Hence, (2 , 12) is a solution for the line C.

Equation of line D is, $\frac {y - 20}{x - 7} =\frac {20 + 7}{7 - 0}$

or, $\frac {y - 20}{x - 7} = \frac {27}{7}$

or, 7y - 140 = 27x - 189

or, 7y - 27x = -49----------------------------------------(4)

The point (2, 12) is not satisfied by (4). hence, (2, 12) is not a solution of the line D

Hence, the pair of equations which has (2,12) as its solution is,

equation B and equation C.

6 0

4 years ago