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liberstina [14]
3 years ago
8

TRUE or FALSE: The equation 2x + 3y = 32 is not an example of a linear equation in two variables ( I uh need this now-)

Mathematics
1 answer:
Cloud [144]3 years ago
5 0

Answer:

False

Step-by-step explanation:

It is a linear equasion because it's in ax+by=c form

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Solve for y.
Svetradugi [14.3K]
1. For y, I think that refers to the first picture attached. As you can see, each side of the triangle have the same short line drawn across it. It means that they are equal in length. That means the triangle is equilateral, which means each interior angle is 60°. Thus,

60 = 5y + 10
5y = 60 - 10
5y = 50
y = 50/5 =<em> 10</em>

2. As you can see in the second picture attached, Angles B and C are equal. That also means that their respective opposite sides are equal. So,

8x - 4 = 5x + 11
8x - 5x = 11 + 4
3x = 15
x = 15/3 = 5

Consequently,
BC = 4x - 2
BC = 4(5) - 2 = <em>18</em>
4 0
4 years ago
Read 2 more answers
Find the value of x and the value of y.
jeka57 [31]

Answer:

x =  6/√3  ,   y = 12/√3

Step-by-step explanation:

sin 60° = opposite /hypothenus

√3/2 = 6/y

cross multiply

√3y=6 x 2 = 12

y = 12/√3

Tan 60° = opposite/adjacent

tan 60° = √3

√3 = 6/x

√3x= 6

x = 6/√3

7 0
4 years ago
I need help please!!!! <br> No links aloud
Verdich [7]

Answer:

the second one.

Step-by-step explanation:

7 0
3 years ago
garett uses 5 apples to bake an apple pie on sunday he bkes 2 pies how many apples does garett need on sunday write an equation
adoni [48]

Answer:

2+x=5

Step-by-step explanation:

i think dont bash me

6 0
3 years ago
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Write the equation in siope-intercept form for the line that passes through the given pointand is perpendicular to the given equ
yulyashka [42]

For a line in the form:

\begin{gathered} ax+by=c \\ The\text{ slope m is:} \\ m=-\frac{a}{b} \end{gathered}

In this case, for the line 2x + 10y = 20 with a=2 and b=10 the slope is:

\begin{gathered} m_1=-\frac{a}{b}=-\frac{2}{10} \\ m_1=-\frac{1}{5} \end{gathered}

Now, two lines are perpendiculars if the slopes satisfy the following equation:

m_2=-\frac{1}{m_1}

So, for the line we want the slope is:

\begin{gathered} m_1=-\frac{1}{5} \\ m_2=-\frac{1}{m_1}=-\frac{1}{(-\frac{1}{5})}=5 \end{gathered}

Finally, the line pass througth the point (2, 3) with slope m=5, so the equation is:

\begin{gathered} P_1=(2,3),m=5 \\ y=mx+b \\ \text{The P1 must satisfy the equation:} \\ 3=5\cdot2+b \\ b=3-10 \\ b=-7 \end{gathered}

The equation of the line is y = 5x - 7

7 0
1 year ago
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