1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tekilochka [14]
3 years ago
15

SHOW YOUR WORK. 44.22 divided by (-6.7) and -6.46 divided by 0.04​

Mathematics
1 answer:
zimovet [89]3 years ago
3 0

Answer: -6.6 and -161.5

Step-by-step explanation: 44.22/-6.7=-6.7 -6.46/.04=-161.5 <——- not to sure about that one

You might be interested in
161 divided by 4 , need a pic with the answer....
ludmilkaskok [199]

Answer:

40.25 if my math is right

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Danny wants to buy a truck in 4 years. He is going to put away $2,500.00 into his savings account that will pay him 6.75% intere
aniked [119]

Answer:

b $3,272.43

Step-by-step explanation:

A = p(1+r/n)^nt

Where

A= future value

P= principal = $2500

r= interest rate = 6.75% = 0.0675

n = number of periods = 12

t = time = 4 years

A = p(1+r/n)^nt

= 2500(1+0.0675/12)^12*4

= 2500(1+0.005625)^48

= 2500(1.005625)^48

= 2500(1.3089737859257)

= 3272.4344648144

Approximately

A= $3272.43

He will have $3272.43 to give as down payment in 4 years

4 0
3 years ago
How many Solutions does 5p + 3 = 5p - 1 have?
Tresset [83]
No solution because 3=-1 isn’t true.
4 0
3 years ago
A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0
3 years ago
(Multi Step Algebra)<br>15x+12=19x-24<br>what is the answer? help me please ​
solmaris [256]

9

Step-by-step explanation:

15x+12=19x-24

15x-19x=-24-12

-4x=-36/÷(-4)

x=9

You first put all the x on one side and numbers on the other and be careful about + and - and then you divide by everything with the x so you have only the x left and you get the aswer.

5 0
2 years ago
Read 2 more answers
Other questions:
  • Use the Pythagorean theorem to find the distance form Emma’s house to the pool
    13·1 answer
  • How do i find the height??? ​
    10·2 answers
  • Indicate a general rule for the nth term of the sequence a1 = 2 and r = √3.
    6·1 answer
  • A number between 10.2 and 10.3 is
    9·2 answers
  • If Jo is supposed to read one-half of a 100-page book for an English assignment and she has finished 38 pages, what percent of t
    8·1 answer
  • Triangle ABC is rotated 180° using the origin as the center of rotation.
    13·1 answer
  • In a bag of 18 oranges, 12 have gone bad.<br><br> What is the ratio of good oranges to bad oranges?
    12·1 answer
  • Which of the following could be a solution to a system of linear equations including the line graphed below?
    13·1 answer
  • One angle in a complementary pair of angles measures 3 times the other angle.
    14·1 answer
  • PLS ANSWER BOTH PARTS I WILL GIVE BRAINLIEST PLSSS HURRRYYYY
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!