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9966 [12]
3 years ago
15

Which table represents a quadratic function?

Mathematics
1 answer:
Ganezh [65]3 years ago
5 0

9514 1404 393

Answer:

  see below

Step-by-step explanation:

The x-values in each table are evenly-spaced (increasing by 2). So, the quadratic function can be identified by its second differences: they will be a non-zero constant.

Table 1 has first differences that are constant at 3. -2-(-5) = 3, for example. It represents a linear function.

Table 2 has first differences of 4, 8, 4, 4, neither constant, nor linearly increasing. The function does not have a name.

Table 3 has first differences of -9, -3, +3, +9, and these have differences of +6. This represents a quadratic function.

Table 4 has first differences of 0.5, 1, 2, 4. These have a constant ratio, as do the values in the table. It represents an exponential function.

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Please help me on this problem
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The pairs of integer having two real solution forax^{2} -6x+c = 0 are

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Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

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2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

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