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emmainna [20.7K]
3 years ago
9

PLEASE HELP!! WILL BE MARKED BRAILIEST

Biology
1 answer:
mash [69]3 years ago
6 0

Answer:

Answer is Ascomycota.

Explanation:

I hope it's helpful!

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Pros and cons of penguins in huddles
shtirl [24]

Answer:

Pro: Warmeth for the cold

Con: Big dinner for predators

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This image is of a human embryo I took many weeks of development to get to the stage prior to this all the human cells were not
seraphim [82]
Stem Cells aren't differentiated.

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Consider the characteristics of moss and fern life cycles. Which of the following sets of statements is true?A. The gametophyte
Paraphin [41]

Answer:

E) In both mosses and ferns, moisture is required for sperm to reach the egg. In mosses, gametophyte is the dominant stage of the life cycle. In ferns, the sporophyte is the dominant stage of the life cycle.

Explanation:

The *sporophyte of fern plant is dominant over the smaller and nutritionally independent gametophyte*. The sporophytes are photosynthetic, long-lived and highly branched. *Sperm cells of fern possess whip-like flagella in their cell walls that enable moisture swim to reach the egg*

*In Mosses,the gametophyte is more prominent (dominant)* just like in lower plants. These organisms *require external water(moisture) in the form of dew or rain to move their sperm during fertilization*.

Therefore, *In ferns, the sporophyte is dominant over the gametophyte*, while *in mosses,gamatophyte is dominant over the sporophyte.* Both require moisture for sperm to reach egg.

5 0
3 years ago
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Pumps are transporters that are able to harness energy provided by other components in the cells to drive the movement of solute
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This type of transport is called active transport
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For this question, we will utilize a population of Martians that is in Hardy Weinberg Equilibrium. The dominant Martian phenotyp
Brrunno [24]

Answer:

d.0.48

Explanation:

When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:

freq (AA) = p²

freq (Aa) = 2pq

freq (aa) = q²

<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.

In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.

Therefore:

q²=16/100

q² = 0.16

q=√0.16

q = 0.4

And p+q=1, so:

p = 1 - q

p = 1-0.4

p = 0.6

The frequency of heterozygotes is:

freq (Aa) = 2pq = 2 × 0.4 × 0.6

freq (Aa) = 0.48

5 0
3 years ago
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