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3 years ago

9

32.8g of sugar is needed to make 4 cakes. How much sugar is needed for 7 cakes?

1 answer:

allochka39001 [22]3 years ago

6 0

Answer:

57.4g

Step-by-step explanation:

32.8g of sugar is needed to make 4 cakes. How much sugar is needed for 7 cakes?

From the above questions, we know that:

4 cakes = 32.8g

7 cakes = x g

Cross Multiply

4 × xg = 7 × 32.8g

x = 7 × 32.8g/4

x = 57.4 g

Therefore, 57.4g is needed for 7 cakes

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Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior citizen tickets and 4 child ticke

FrozenT [24]

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?

14S + 4C = 200

14S = 200 - 4C

S = (200 - 4C)/14

7S + 1C = 92

7S = 92 - C

S = (92 - C)/7

(200 - 4C)/14 = (92 - C)/7

7 x (200 - 4C) = 14 x (92 - C)

1400 - 28C = 1288 - 14C

1400 - 1288 = 28C - 14C

112 = 14C

C = 112/14 = 8

the price of one child ticket = $8

8 0

3 years ago

I need help again please!!

ivann1987 [24]

Answer c because .10 x 40 equals 4 plus 2

3 0

3 years ago

Read 2 more answers

Find the mean, median, and mode of the data, if possible. If any of these measures cannot be found or a measure does not repre

Contact [7]

Answer:

1. Median = 10.1

2. A. The median represents the center.

3. D. The mode(s) can't represent the center because it (they) is(are) not a data value.

Step-by-step explanation:

Mean of a sample = sum of the samples/no of the samples

Samples in increasing order:

9.8

9.8

9.9

10.1

10.4

10.6

11.1

Mode is the sample with highest frequency.

Median is the middle entry of the data.

Mean = (9.8 + 9.8 + 9.9 + 10.1 + 10.4 + 10.6 + 11.1)/7

= 717/7

= 10.243

Median = 10.1

Mode = 9.8 because it has the highest frequency of 2

6 0

3 years ago

If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that

Ivan

Answer:

$\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}$

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• $\sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}$

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

• $\sf\implies cos2A =\dfrac{\sqrt3}{2}$

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

$\sf\implies cos2A = 1 - 2sin^2A$

Therefore , here substituting the value of sinA , we have ,

$\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2$

Simplify the whole square ,

$\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}$

Add the numbers in numerator ,

$\sf\implies cos2A = 1-2\times \dfrac{4-2\sqrt3}{8}$

Multiply it by 2 ,

$\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}$

Take out 2 common from the numerator ,

$\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}$

Simplify ,

$\sf\implies cos2A = 1 -\dfrac{ 2-\sqrt3}{2}$

Subtract the numbers ,

$\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}$

Simplify,

$\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }$

Hence Proved !

8 0

3 years ago

Find the arc length of the partial circle.

Kay [80]

Answer:

12.42 units

Step by step explanation:

Given,

length of the radius = 2 units

Therefore, arc length of the complete circle = 2 × 3.14 × 2 units = 12.56 units

Therefore, arc length of the partial circle = 3/4 × 12.56 units

= 12.42 units

3 0

3 years ago