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babymother [125]
3 years ago
14

The administrator of a small town received a certain number of complaints during the last two weeks. What are the three sigma co

ntrol limits for the number of complaints received each day using the following data? Is the process in control? Day = 1 2 3 4 5 6 7 8 Number of complaints = 6 11 15 10 4 9 3 20 UCL = 21.253, LCL = 1.562 and in control. UCL = 22.118, LCL = 2.371 and in control. UCL = 22.118, LCL = 2.371 and NOT in control. UCL = 19.118, LCL = 0.383 and in control. UCL = 19.118, LCL = 0.383 and NOT in control.
Business
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Solution:

Calculate mean of the sample data as shown below :

x (bar) = \frac{6 + 11 + 15 + 10+ 4+ 9 +3+ 20}{8}

          = 60.5

Calculate the upper and lower control limits as below :

UCL = x (bar) + z\sqrt{x(bar)}

       = 60.5 + 3 \sqrt{60.5}

      =  60.5 + 3 ( 7.778 )

      = 83.834

LCL = x (bar) - z\sqrt{x(bar)}

      = 60.5 - 3 ( 7.778 )

      = -37.166

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