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Mrrafil [7]
3 years ago
7

Please help me!!! it´s due in a HOUR (answer these questions but also can you show me how you do it to :> thanks)

Mathematics
1 answer:
evablogger [386]3 years ago
4 0

Answer:

\frac{1}{3}

Step-by-step explanation:

\frac{1}{2}(\frac{1}{3}) + \frac{1}{6}           \frac{1}{2} x \frac{1}{3} = \frac{1}{6}           \frac{1}{6} + \frac{1}{6} = \frac{2}{6}           \frac{2}{6} = \frac{1}{3}

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6 0
3 years ago
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The length of time to complete a door assembly on an automobile factory assembly line is normally distributed with a mean of 6.7
hram777 [196]
We need to work out the z-value of each question to work out the probability

Question a)

We have
X = 5 minutes
The mean, μ = 6.7 minutes
Standard deviation, σ = 2.2 minutes
z-score = (X - μ) / σ = (5 - 6.7) / 2.2 = -0.77

We want to find the probability of z < -0.77 so we read the z-table for the value of z on the left of -0.77 we have the probability P(z< -0.77) = 0.2206

The table is attached in picture 1 below

The probability of assembly time less than 5 minutes is 0.2206 = 22.06%

Question b)

z-score = (10-5) / 2.2 = 2.27

Reading the z-table for P(z<2.27) = 0.9884
The table reading is shown in the second picture below

The probability the assembly time will be less than 10 minutes is 0.9884

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Question c)

The value of z between 5 minutes and 10 minutes is

P(-0.77<z<2.27) = P(z<2.27) - P(z< -0.77)
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6 0
3 years ago
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