Please help me!!! it´s due in a HOUR (answer these questions but also can you show me how you do it to :> thanks)

Mathematics

1 answer:

evablogger [386]3 years ago

4 0

Answer:

$\frac{1}{3}$

Step-by-step explanation:

$\frac{1}{2}$ ( $\frac{1}{3}$ ) + $\frac{1}{6}$ $\frac{1}{2}$ x $\frac{1}{3}$ = $\frac{1}{6}$ $\frac{1}{6}$ + $\frac{1}{6}$ = $\frac{2}{6}$ $\frac{2}{6}$ = $\frac{1}{3}$

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Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$