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3 years ago

5. Troy wants to find the distance between his house on one side of the park and his school on the other

Mathematics

1 answer:

VLD [36.1K]3 years ago

3 0

Answer:

well

Step-by-step explanation:

why the hell would troy want to do that when he could really just go home and play fortnite

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Write rule for the linear function in the table

ivann1987 [24]

The generic equation is:
y-yo = m (x-xo)
Where,
m = (y2-y1) / (x2-x1)
m = (0-1) / (4-3)
m = (- 1) / (1)
m = -1
The ordered pair is:
(xo, yo) = (4, 0)
Substituting values:
y-0 = -1 * (x-4)
y = -x + 4
Answer:
y = -x + 4
option 1

8 0

4 years ago

Which of the following expressions is equivalent to the logarithmic expression below? HELP PLEASE HELP ME PLEASE PLEASE HELP PLE

IrinaK [193]

Using log rules:
when you divide and then sperate you subtract.
So
Log3(5/x^2) would be A
Log3(5)-Log3(x^2)

4 0

4 years ago

Plz Help!!!!!!!!!!!!!!!!!!!

Natasha2012 [34]

Answer:

x = 4

Step-by-step explanation:

5[3(x + 4) - 2(1 - x)] - x - 25 = 14x + 65

Distribute by 3 and 2 inside the square bracket

5 [ 3x + 12 - 2 + 2x ] - x - 25 = 14x + 65

collect like terms inside the square bracket

5 (5x + 10) - x - 25 = 14x + 65 ← distribute the parenthesis by 5

25x + 50 - x - 25 = 14x + 65 ← collect like terms on left side

24x + 25 = 14x + 65 ( subtract 14x from both sides )

10x + 25 = 65 ( subtract 25 from both sides )

10x = 40 ( divide both sides by 10 )

x = 4

8 0

4 years ago

An airplane travels at 120 km/hr for 2 hours in a direction of 260° . At the end of this time, how far south.Of the airport is t

nadezda [96]

Answer:

the airplane is 130.56 km south of the airport after 2 hours

Step-by-step explanation:

given data

travel speed = 120

time travel = 2 hour

direction = 260°

solution

we get here direst distance covered by plane in 2 hours that is

distance cover = 120 × 2

distance cover = 240 kilometers

and

the south component of the distance will be here as

distance = 240 × sin(270 - 260) = - 130.56

so the airplane is 130.56 km south of the airport after 2 hours

3 0

3 years ago

Researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day. At the local high school,

Nataliya [291]

Answer:

We conclude that 18% of all high school students smoke at least one pack of cigarettes a day.

Step-by-step explanation:

We are given that researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day.

At the local high school, a randomly selected sample of 300 students found that 50 students smoked at least one pack of cigarettes a day.

Let p = proportion of all high school students who smoke at least one pack of cigarettes a day.

So, Null Hypothesis, $H_0$ : p = 18% {means that 18% of all high school students smoke at least one pack of cigarettes a day}

Alternate Hypothesis, $H_A$ : p < 18% {means that less than 18% of all high school students smoke at least one pack of cigarettes a day}

The test statistics that would be used here is One-sample z -test for proportions because we are given with the proportions values;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who smoked at least one pack of cigarettes a day = $\frac{50}{300}$ = 0.167

n = sample of students = 300

So, test statistics = $\frac{0.167-0.18}{\sqrt{\frac{0.167(1-0.167)}{300} } }$

= -0.604

The value of z test statistics is -0.604.

Also, P-value of the test statistics is given to us is 0.2743.

Since, the P-value of test statistics is more than the level of significance as 0.2743 > 0.025, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 18% of all high school students smoke at least one pack of cigarettes a day.

6 0

3 years ago