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Zanzabum
3 years ago
15

So are you good at maths then what is

Mathematics
2 answers:
Travka [436]3 years ago
6 0
Answer: 28

Order of operations is key here. So multiply first. Then you just add/subtract left to right.

24 + 9 - 46 + 54 - 13
33 - 46 + 54 - 13
-13 + 54 - 13
41 - 13
= 28
quester [9]3 years ago
4 0

maybe 28 is the answer...

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H(t)=-16(t-1)^2+16 <br> What is the maximum height the ball reaches and how long does it take?
Aleksandr-060686 [28]

Given t = time and h = height

h(t) =  - 16(t - 1)^{2}  + 16

From the equation.

y = a(x - h)^{2}  + k

h is the axis od symmetry

(h, k) is the vertex.

In the equation, h is 1 and k is 16.

So the maximum value is 16 at t = 1.

The ball reaches maximum at 16 and it takes t = 1 to reach the maximum point.

4 0
2 years ago
The ratio of boys to girls in a group is 7:3. If there are 40 more boys than girls, work out how many people there are in total.
LenaWriter [7]

Answer:

Step-by-step explanation:

7 - 3 = 4

7 + 3 = 10

4/10 = 40

10/10 = ?

10/10 x 40 x 10/4

= 100 people

7 0
3 years ago
At the end of the year a car is worth 5% less than what it was worth at the beginning of the year. If a car was worth $9 500 in
Pepsi [2]
The answer should be 9025
3 0
3 years ago
Read 2 more answers
Solve the equation x/4 - 7 = y for x
expeople1 [14]

Answer:

x = 4y + 28

Step-by-step explanation:

x/4 - 7 = y

+7              +7

x/4 = y + 7

× 4             × 4

x = 4y + 28

7 0
3 years ago
Read 2 more answers
Plz plz help me so i can get a good grade
Levart [38]

Area of the figure = 806.5 in²

Solution:

Length of the rectangle = 16 in

Breadth of the rectangle = 9 in

Area of the rectangle = length × breadth

                                    = 16 × 9

Area of the rectangle = 144 in²

Base of the triangle = 31 in

Height of the triangle = 20 in

Area of the triangle = \frac{1}{2}bh

                                 $=\frac{1}{2}\times 31\times 20

Area of the triangle = 310 in²

Parallel sides of the trapezium = 16 in and 31 in

Height of the trapezium = 35 – 20 = 15 in

Area of the trapezium = \frac{1}{2}\times \text{Sum of the parallel sides}\times \text{Height}

                                     $=\frac{1}{2}\times {(16+31)}\times{15}

                                     $=\frac{1}{2}\times {47}\times{15}

Area of the trapezium = 352.5 in²

Area of the figure = Area of rectangle + Area of triangle + Area of trapezium

                              = 144 in² + 310 in² + 352.5 in²

Area of the figure = 806.5 in²

8 0
3 years ago
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