There are several shapes that fulfill these requirements. All involve to parallel rows of 4, then the other two trees forming a perpendicular for (using a tree from each of the other two rows).
E.g.
X X X X
X X X X
X
X
X X X X
X
X
X X X X
X X X X
X
X X X X
X
I think its a) 172.50 but im not exactly sure.
X=3 because you subtract the three on both sides to get x alone. So you get: 7x=21 then you divide seven by 21 and get x=3
Answer:
B
=
P/
2
−
M
Step-by-step explanation:
Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8
