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larisa86 [58]
3 years ago
12

The two different bacteria are growing in a lab. the following functions represent the bacteria.

Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer :

Bacteria B started with 3000 bacteria.

Bacteria B doubles every hour.

In three hours, the amount of Bacteria A will be greater than the amount of Bacteria B.

Bacteria A: f(x)=  1000 *3^x

x=0 , y = 1000

x=1 , y = 3000

x=2 , y = 9000

x=3 , y = 27000

Bacteria A: f(x)=  3000 *2^x

x=0 , y = 3000

x=1 , y = 6000

x=2 , y = 12000

x=3 , y = 24000

From this table we can see that Bacteria B started with 3000 bacteria.

Bacteria B doubles every hour, 3000, 6000, 12000, 24000

In 3 hours , Bacteria A = 27000 and Bacteria B = 24000

So,In three hours, the amount of Bacteria A will be greater than the amount of Bacteria B.

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Answer:

P(X \geq 2) = 1-P(X

And we can find the individual probabilities using the probability mass function and we got:

P(X=0) = (30C0) (0.05)^0 (1-0.05)^{30-0} =0.2146

P(X=1) = (30C1) (0.05)^1 (1-0.05)^{30-1} = 0.3389

And replacing we got:

P(X \geq 2) = 1-P(X

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=30, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Solution to the problem

For this case we want this probability:

P(X \geq 2)

And we can use the complement rule and we got:

P(X \geq 2) = 1-P(X

And we can find the individual probabilities using the probability mass function and we got:

P(X=0) = (30C0) (0.05)^0 (1-0.05)^{30-0} =0.2146

P(X=1) = (30C1) (0.05)^1 (1-0.05)^{30-1} = 0.3389

And replacing we got:

P(X \geq 2) = 1-P(X

3 0
3 years ago
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