The genotypes would be bbTT X BbTt
Assuming that bark color is represented by B (b) allele and height is represented by T (t) allele.
Since the traits show simple dominance: blue (B) of dominant over purple (b) and tall (T) is dominant over short (t)
- The genotype of a tree that is purebred purple (bb) and tall (TT) would be bbTT
- The genotype of a tree that is heterozygous for both trait would be BbTt
- Thus, the cross would be bbTT x BbTt
More on genotypes can be found here: brainly.com/question/20730322?referrer=searchResults
0%?... i mean if 100 million years is half of its life then 300 million years surpasses its entire lifetime which would be 200 million years. Based off of this I don’t believe there’d be anything left
The answer is;
- The recombination frequency is proportional to the distance between the two genes
- The lower the recombination frequency, the farther apart two genes are on the chromosome
Genes that are close together are more likely to be passed together to offspring during recombination. Geneticist compares the ration between the proposed phenotype offspring and actual phenotype offerings in a population. The higher the recombination frequency (centimorgans," or cM), the closer the genes are linked together, physically.
Answer: C. higher
Neurological and perceptual speeds are generally higher in individuals with <u>higher</u> intelligence.
