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3 years ago

What is 3425030 in scientific notation

Mathematics

1 answer:

dem82 [27]3 years ago

7 0

The answer is 3.42 x 10^6 because we moved the decimal 6 places to the left. Hope this helps:)

~Ash

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thirty five percent of the revenue produced at the auction will go to the charity. the morning participants spent an average of

spin [16.1K]

I'm not sure that I am 100% right but I'll give it a shot.
50+75= 125*0.35=43.75
$43.75

4 0

2 years ago

Which equation shows how (-10,8) can be used to write the equation of this line in point-slope from?

NeTakaya

Options :

y – 8 = –0.15(x – 10)

y + 8 = –0.15(x – 10)

y – 8 = –0.2(x + 10)

y + 8 = –0.2(x – 10)

Answer:

y – 8 = –0.2(x + 10)

Step-by-step explanation:

(-10, 8)

General equation in point - slope form:

y - y1 = m(x - x1)

m = slope

Given the points : ( - 10, 8)

x1= - 10 ; y1 = 8

y - y1 = m(x - x1)

Substitute the values of x and y into the equation :

y - 8 = m(x - - 10)

y - 8 = m(x + 10)

The best option which fits is :

y – 8 = –0.2(x + 10)

6 0

3 years ago

Read 2 more answers

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}$

part B) check the picture below

5 0

2 years ago

In a sample of 1000 cases, the mean of a certain test is 14 and the standard deviation is 2.5. Assume the distribution to be nor

Maslowich

Answer:

The top 20% of the students will score at least 2.1 points above the mean.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The mean of a certain test is 14 and the standard deviation is 2.5.

This means that $\mu = 14, \sigma = 2.5$