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Zielflug [23.3K]
3 years ago
11

An insect crawls up 5cm every second on a 6cm vertical rod and then falls down 2cm over the next second. How many seconds will i

t take to climb the rod?​
Mathematics
1 answer:
makkiz [27]3 years ago
3 0

Answer:

3 seconds

Step-by-step explanation:

It's quite simple. First, add 5cm to the progress of the insect, counting it as 1 second. Then subtract 2cm because it falls over the next second, thus taking another second. Then finally, plus 5cm, making it 3 seconds. It's not 4 seconds because at 3 seconds it had already reached the top.

If I didn't clear everything or messed up, please comment.

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Step-by-step explanation:

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The diffrence between an integer p and (-5) is 1 find the value of p ​
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Solution:

<u>Note that:</u>

  • Given sentence: The difference between an integer p and (-5) is 1.

<u>Let's reread the sentence carefully.</u>

The difference between an integer p and (-5) is 1.

  • => p - (-5) = 1

<u>Change the sign.</u>

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<u>Subtract 5 both sides:</u>

  • p + 5 = 1
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A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob
Musya8 [376]

Let p be the population proportion. <span>
We have p=0.60, n=200 and we are asked to find P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012. 
So, the probability that the sample proportion is less than 0.58 
= P(^p<0.58) 
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0... 
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