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3 years ago

Factor out the GCF of the three terms, then complete the factorization of 6x3 + 6x2 – 1202.

Mathematics

1 answer:

Fittoniya [83]3 years ago

3 0

Answer : 2( 3x^3 +3x^2 - 601 )

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Can someone help me asap

Alenkasestr [34]

Answer:

I hope this is helpful

Step-by-step explanation:

mark brainlest pls

4 0

2 years ago

How do you work this out?

Katarina [22]

Because ABCD is a rectangle, the length of CD is 12 cm.

We need to determine the length of DE. If we can do that, then the sum of the lengths of CD and DE represents the unknown: the length of CE.

To find the length of CE, we have to "solve" the upper triangle.

Here's an outline of what to do:

1. Show that BC=AD and find the length.
2. Note that angle CAD is 60 degrees. Why?
3. Note that angle EAD is 30 degrees. Why?
4. Find the length of ED
5. Add ED and DC, that is, ED + 12 cm. This is your answer.

Please ask questions if need be.

5 0

2 years ago

The two triangleshaped gardens are congruent. Find all of the missing side lengths and angle measures. Show any necessary work

pantera1 [17]

The two figures are in the file attached.

Congruency means that all the respcetive sides and angles are equals.

Then, the three angles are :

y = 38°

x = 90°

w = 180° - 90° - 38° = 52

The three sides are:

z= 10yd
v= 7.9yd
u=6.2yd

You have all the measures as a function of yd, but you do not have any information about yd, then it is not possible to find the real lenghts.

All you can tell is that the sides obey Pythagoream theorem:

u^2 + v^2 = z^2

But that is not enough to find one side, because you do not know any of them.

For example if you apply Pytagorean theorem you cand do"

(7.9yd)^2 + (6.2)^2 = (10yd)^2

but that cannot be solved for yd, because they are factors of all the terms in both sides, which mean that they cancel to obtain:

(7.9)^2 + (6.2)^2 = (10)^2, which is not any new information.

Also you can think about sine theorem, but it does not help, because you also need one side.

Then you only can tell the missing angles, as I have shown, but not the misssing lengths.

Download docx

8 0

2 years ago

COMPUTE 3 ( 2 1/2 - 1 ) + 3/10

Juli2301 [7.4K]

Answer:

<h3> $\boxed{ \frac{24}{5} }$ </h3>

Step-by-step explanation:

$\mathsf{3(2 \frac{1}{2} - 1) + \frac{3}{10} }$

Convert mixed number to improper fraction

$\mathrm{3( \frac{5}{2} - 1) + \frac{3}{10} }$

Calculate the difference

⇒ $\mathrm{3( \frac{5 \times 1}{2 \times 1} - \frac{1 \times 2}{1 \times 2} }) + \frac{3}{10}$

⇒ $\mathrm{ 3 \times( \frac{5}{2} - \frac{2}{2}) } + \frac{3}{10}$

⇒ $\mathrm{3 \times ( \frac{5 - 2}{2} ) + \frac{3}{10} }$

⇒ $\mathrm{3 \times \frac{3}{2} + \frac{3}{10} }$

Calculate the product

⇒ $\mathrm{ \frac{3 \times 3}{1 \times 2} + \frac{3}{10} }$

⇒ $\mathrm{ \frac{9}{2} + \frac{3}{10}}$

Add the fractions

⇒ $\mathsf{ \frac{9 \times 5}{2 \times 5} + \frac{3 \times 1}{10 \times 1} }$

⇒ $\mathrm{ \frac{45}{10} + \frac{3}{10} }$

⇒ $\mathrm{ \frac{45 + 3}{10 } }$

⇒ $\mathrm{ \frac{48}{10} }$

Reduce the numerator and denominator by 2

⇒ $\mathrm{ \frac{24}{5} }$

Further more explanation:

Addition and Subtraction of like fractions

While performing the addition and subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.

For example :

Add : $\mathsf{ \frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} } = \frac{4}{5}$

Subtract : $\mathsf{ \frac{5}{7} - \frac{4}{7} = \frac{5 - 4}{7} = \frac{3}{7} }$

So, sum of like fractions : $\mathsf{ = \frac{sum \: of \: their \: number}{common \: denominator} }$

Difference of like fractions : $\mathsf{ \frac{difference \: of \: their \: numerator}{common \: denominator} }$

Addition and subtraction of unlike fractions

While performing the addition and subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus, obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator.

For example:

$\mathsf{add \: \frac{1}{2} \: and \: \frac{1}{3} }$

L.C.M of 2 and 3 = 6

So, ⇒ $\mathsf{ \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} }$

⇒ $\mathsf{ \frac{3}{6} + \frac{2}{6} }$

⇒ $\frac{5}{6}$

Multiplication of fractions

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

When any number or fraction is divided by a fraction, we multiply the dividend by reciprocal of the divisor. Let's consider a multiplication of a whole number by a fraction:

$\mathsf{4 \times \frac{3}{2} = \frac{4 \times 3}{2} = \frac{12}{2} = 6}$

Multiplication for $\mathsf{ \frac{6}{5} \: and \: \frac{25}{3} }$ is done by the similar process

$\mathsf{ = \frac{6}{5} \times \frac{25}{3} = 2 \times 5 \times 10}$

Hope I helped!

Best regards!

5 0

3 years ago

Problem page the sum of two numbers is 56 . the smaller number is 16 less than the larger number. what are the numbers?

igomit [66]

Create equations using the given information
1) x+y=56
2) y=x-16
Substitute the value of y into the 1st equation and simplify
1)x+x-16=56
2x=72
x=36
Substitute the value of x into the 1st equation and simplify
1)x+y=56
36+y=56
y=20

Answer: 20 and 36

8 0

3 years ago