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g100num [7]
3 years ago
6

How the number e was discover

Mathematics
2 answers:
Vaselesa [24]3 years ago
5 0

Answer:

It was that great mathematician Leonhard Euler who discovered the number e and calculated its value to 23 decimal places. It is often called Euler's number and, like pi, is a transcendental number (this means it is not the root of any algebraic equation with integer coefficients

aalyn [17]3 years ago
3 0
Dvzhrcvvxxn. Ik sorry
You might be interested in
During a chemical reaction, the function y=f(t) models the amount of a substance present, in grams, at time t seconds. At the st
PtichkaEL [24]

Answer:

The solution of differential equation =

y = \boldsymbol{\frac{10}{.2t - 1}}

Step-by-step explanation:

Given-

y=f(t) models the amount of a substance present, in grams, at time t seconds

when t = 0  then y = 10

the differential equation is

\boldsymbol{\frac{\mathrm{d} y}{\mathrm{d} t} = -0.02 y^{2}}

\frac{\mathrm{d} y}{y^{2}} = -0.02\mathrm{d} t

Integrate both side

\int \frac{\mathrm{d} y}{y^{2}} = \int -0.02\mathrm{d} t

\frac{y^{-2 + 1}}{-2 + 1} = -.02\times t + C

\frac{- 1 }{y} = -.02\times t + C

when t = 0  then y = 10

\frac{- 1 }{10} = -.02\times 0 + C

C = \frac{- 1 }{10}

\frac{- 1 }{y} = -.02\times t - \frac{ 1 }{10}

\frac{ 1 }{y} = .02\times t - \frac{ 1 }{10}

\frac{ 1 }{y} = \frac{.2t - 1}{10}

y = \frac{10}{.2t - 1}

5 0
3 years ago
What are the solutions to the equation 3x^2 + 15x = 18. Show your work.
balandron [24]

Assignment: \bold{Solve \ Equation: \ 3x^2+15x=18}

<><><><><><><>

Answer: \boxed{\bold{x=1,\:x=-6}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Subtract 18 From Both Sides

\bold{3x^2+15x-18=18-18}

[ Step Two ] Simplify

\bold{3x^2+15x-18=0}

[ Step Three ] Solve With Quadratic Formula

Note: \bold{For\:a\:quadratic\:equation\:of\:the\:form\: ax^2+bx+c=0}

\bold{the \ solutions \ are \ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}

\bold{a=3,\:b=15,\:c=-18:\quad x_{1,\:2}=\frac{-15\pm \sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}}

<><><><><><><>

\bold{\frac{-15+\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ 1}

\bold{\frac{-15-\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ -6}

[ Step Four ] Combine Solutions

\bold{x=1,\:x=-6}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

5 0
2 years ago
Read 2 more answers
Help me with it I will give you 20 points ​
cupoosta [38]

Answer:

a^2 +b^2=c^2

Given vertices of the triangle are A(4,4),B(3,5) and C(−1,−1)

We know that slope of line passing through the points (x 1,y 1) and (x 2,y 2

) is given by m= x 2−x 1

y

2

​

−y

1

​

​

,x

2

​



=x

1

​

Slope of AB i.e.m

1

​

=

3−4

5−4

​

=−1

Slope of BC i.e.m

2

​

=

−1−3

−1−5

​

=

−4

−6

​

=

2

3

​

Slope of CA i.e. m

3

​

=

4+1

4+1

​

=

5

5

​

=1

Clearly, m

1

​

m

3

​

=−1

⇒ line segments AB and CA are perpendicular to each other i.e; the given triangle is right angled at A(4,4).

Thus the points (4,4),(3,5) and (1,1) are the vertices of a right angled triangle.

Step-by-step explanation:

4 0
2 years ago
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
3 years ago
How do you find mode in data
nikdorinn [45]

Answer:

The mode is the number that shows up most frequently

Step-by-step explanation:

Example, in the number set below

1, 1, 2, 3, 4, 4, 4, 4, 5, 7, 35, 36

The mode is 4

4 0
3 years ago
Read 2 more answers
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