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2 years ago

I need HELP ASAP! It’s due today

Mathematics

2 answers:

Vikki [24]2 years ago

8 0

Answer:

28 cubs

Step-by-step explanation:

Since one and a half bear produces one and a half cub, then 6 bears will produce 6 cubs in one and a half days.

We need to find 7 days, though but we have the rate for six bears for 1.5 days which 6 bears one a half day.

What is the rate for a day?

6/1.5 =

6 bears produce 4 cubs a day.

Now just do 4 x 7

4 x 7 = 28

Therefore, 6 bears produce 28 cubs in 7 days.

riadik2000 [5.3K]2 years ago

5 0

28 Cubs is the answer

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2 years ago

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Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

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2 years ago

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2 years ago

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Step-by-step explanation:

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3 years ago

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miss Akunina [59]

Answer:

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Step-by-step explanation:

What grade r u in?

And what time is where u r?

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2 years ago

￼￼I need HELP ASAP! It’s due today

I need HELP ASAP! It’s due today