Answer:
Jesse needs to work 43 hours in the month to make $400 and $60
work for answer: 9.50 x 43 = 408.5
example why it can't be lower or higher than 43 hours 9.50 x 42 = 399 or 9.50 x 44 = 418
Answer: $1,200 + 5.5% + $45,000= 46200.055 or 46200
Step-by-step explanation: All you have to do is just add because if you read the text it has a key word total.
Caleb has a guaranteed minimum salary of $1,200 per month, or 5.5% of his total monthly sales (as commission), whichever is higher. Last month, his <u>total </u>sales were $45,000. What was his gross pay?
Write a C program to compute Matrix Multiplication of two matrices. Use one dimensional array to store each matrix, where each row is stored after another. Hence, the size of the array will be a product of number of rows times number of columns of that matrix. Get number of row and column from user and use variable length array to initialize the size of the two matrices as well as the resultant matrix. Check whether the two matrices can be multiplied or not. Write a getMatrix() function to generate the array elements randomly. Write a printMatrix() function to print the 1D array elements in 2D Matrix format. Also, write another function product(), which multiplies the two matrices and stores in the resultant matrix. With SEED 5, the following output is generated.
Sample Output
Enter the rows and columns of Matrix A with space in between: 3 5
Enter the rows and columns of Matrix B with space in between: 5 4
Matrix A:
8 6 4 1 6
2 9 7 7 5
1 3 1 1 2
Matrix B:
9 5 4 5
9 9 8 1
4 4 3 5
2 6 2 1
4 5 2 4
Product AxB:
168 146 106 91
161 186 125 81
50 52 37 22
In conclusion, the answer is 5x1
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We write an inequality:
This equation cannot be solved using trivial methods found in high-school classes, so we resort to graphical examination.
is a linear function while
is an exponential one (with limit zero as
approaches
). We see that
at approximately
and
.
Indeed, using a computer algebra system such as the ones on modern TI calculators and on many internet sites gives equality at
. By observing our graph, we see that
when
or
.
