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3 years ago

For the right triangles below, find the values of the side lengths a and h . Round your answers to the nearest tenth.

Mathematics

1 answer:

Strike441 [17]3 years ago

7 0

<h2>H is to 3 and d is to 2 Thats my answer #brainliestbunch - _ - </h2>

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Olivia spent $18.00 of the $21.00 from

nexus9112 [7]

Answer:

6/7

Step-by-step explanation:

18/21 dollars is simplified when you divide the fraction by 3 on each number. So you get 6/7 of her money was spent.

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3 years ago

A pizza shop sells a single pizza for 11 dollars. However, at the end of the night, they will sell extra pizzas for 6 dollars ea

xxMikexx [17]

51*11=561 615-561=54 54/6=9
They sold 9 discounted pizzas.

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3 years ago

Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow

jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

$\left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right i^{3}$

Step-by-step explanation:

selecting the first team from n people we have $\left(\begin{array}{ccc}n\\1\\\end{array}\right) = n$ possibility and choosing second team from the rest of n-1 people we have $\left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1$

As { A, B} = {B , A}

Therefore, the total possibility is $\frac{n(n-1)}{2}$

Since our choices are allowed to overlap, the second team is $\frac{n(n-1)}{2}$

Possibility of choosing both teams will be

$\frac{n(n-1)}{2} * \frac{n(n-1)}{2} \\\\= [\frac{n(n-1)}{2}] ^{2}$

We now have the formula

1³ + 2³ + ........... + n³ = $[\frac{n(n+1)}{2}] ^{2}$

1³ + 2³ + ............ + (n-1)³ = $[x^{2} \frac{n(n-1)}{2}] ^{2}$

= $\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] = [\frac{n(n-1)}{2}]^{3}$

4 0

4 years ago

Please help need it quick will give brainliest thanks

Norma-Jean [14]

Use the Pythagorean theorem:

$x^2+8^2=11^2\\\\x^2+64=121\ \ \ |-64\\\\x^2=57\to x=\sqrt{57}\\\\x\approx7.5$

Answer: C. 7.5

8 0

3 years ago

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HELP ME I NEED THE RIGHT ANSWER

Annette [7]

Answer:

the slope is positive 10

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3 years ago