Question

Matthew found a deposit with a diameter that is 102 times as long as Josef's. How many millimeters long is the diameter of Matthew's deposit? Write your answer in standard form and with number names

Answer 1

Answer:

See explanation

Step-by-step explanation:

Represent Mathew with M and Joe with J

The question has missing details as diameter found by Joe is missing.

However, we'll assume a value for this.

Let

J = 1440mm

This implies that

M = 102* J

Substitute 1440mm for J

So:

M = 102 * 1440mm

M = 14280mm

The question say the answer must be in standard form.

The form is written as:

a * 10^n

Where 1 ≤ a ≤ 9 and n is an integer

So,

M = 14280mm becomes

M = 1.4280 * 10⁴mm

M = 1.43 * 10⁴mm (approximated)

So, all you need to do is replace actual measurements of Joe's diameter with 1440m.

Other steps remain the same.