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Zepler [3.9K]
3 years ago
11

Can you help me with this?? please explain

Mathematics
2 answers:
zepelin [54]3 years ago
7 0
Hello!

We separate this into three sections

we are looking for a graph that has a line where x is greater than -3 and less than -2 while the circles not shaded since it does have the or equal to sign

The graphs that have this is the first and the third

Next we can look for the graph that has x greater than or equal to -2 and less than 3 with the one at -2 shaded but the one at 3 not

The graph that follows this is the third graph

The answer is the third one

Hope this helps!
Julli [10]3 years ago
4 0
The only graphs with the right y-values are A and C. Graph A is double-valued at x=3, so is incorrect.

The appropriate choice is
  Graph C
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Please answer correctly! I will mark you as Brainliest!
boyakko [2]
252.828911927301718279402738
3 0
3 years ago
Read 2 more answers
Points ), K and L are collinear with J between L and K. IF KJ = 28 - 3, LK = 9x + 7 and LJ = 4x - 8,
babymother [125]

J, K, and L are collinear

J is between K and L

LK = KJ + LJ

LK = 9x + 7

KJ = 2x - 3

LJ = 4x - 8

9x + 7 = (2x - 3) + (4x - 8)

9x + 7 = (2x + 4x) + (-3 - 8)

9x + 7 = 6x + -11

9x + 7 = 6x - 11

9x + 7 - 7 = 6x - 11 - 7

9x = 6x - 18

9x - 6x = 6x - 6x - 18

3x = -18

x = -6

∴ The value of x is -6

6 0
2 years ago
One month Tammy rented 2 movies and 6 video games for a total of $ 42 . The next month she rented 5 movies and 3 video games for
EastWind [94]

Answer:

The rental cost of one movie is $2.25 and the rental cost of one video game is $6.25

Step-by-step explanation:

Let the rental cost of 1 movie be m.

Let the rental cost of 1 video game be v.

One month, Tammy rented 2 movies and 6 video games for a total of $42. This means that:

2m + 6v = 42 ________ (1)

The next month she rented 5 movies and 3 video games for a total of $30. This means that:

5m + 3v = 30 _________(2)

We now have two simultaneous equations:

2m + 6v = 42 ________ (1)

5m + 3v = 30 _________(2)

Multiply (2) by 2, and we have:

2m + 6v = 42 __________ (1)

10m + 6v = 60 _________ (3)

Subtract (1) from (3):

 10m + 6v = 60

-<u> 2m + 6v = 42</u>

 <u>  8m     =     18</u>

=> m = 18 / 8

m = $2.25

Put the value of m back in (1):

2(2.25) + 6v = 42

4.5 + 6v = 42

=> 6v = 42 - 4.5 = 37.5

v = 37.5 / 6

v = $6.25

Therefore, the rental cost of one movie is $2.25 and the rental cost of one video game is $6.25

5 0
3 years ago
Simplify: −z^3+5k^6−(−z^3+10k^6)
Georgia [21]
-z³ + 5k^6 + z³ -10k^6

(-z³ cancels out with z³)

5k^6 -10k^6

(then subtract)

Answer is -5k^6
6 0
3 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
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