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stiks02 [169]
3 years ago
8

Our solar system is approximately 27,000 light-years from the center of the Milky Way. Therefore, what is true when we observe t

he center of the Milky Way with a telescope?
Mathematics
1 answer:
aalyn [17]3 years ago
5 0

Answer:

We are observing the galactic center as it was 27,000 years ago

Step-by-step explanation:

The Galactic Center, or Galactic Centre, is the rotational center of the Milky Way. It is 8,122 ± 31 parsecs (26,490 ± 100 ly) away from Earth in the direction of the constellations Sagittarius, Ophiuchus, and Scorpius where the Milky Way appears brightest. It coincides with the compact radio source Sagittarius A*

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vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
Whats the answer to 6a+12=2(3a-8)
erastova [34]
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no solution because the equation is false.
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3 years ago
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Alex777 [14]

Answer:

A and E

Step-by-step explanation:

substitute and odd number into every equation :)

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Nina [5.8K]
I think that the best answer here would be that A = 40 degrees. 
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3 years ago
Which fraction would make this equation true 5×?=6 1/4​
Blizzard [7]

The answer is 1 1/4.

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