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3 years ago

Who ever gets this will get a brainlest

Mathematics

2 answers:

andrew11 [14]3 years ago

7 0

Here’s a picture of my work. The answer is 30 hope this helps :-)

Lorico [155]3 years ago

5 0

Answer:

i think 30

Step-by-step explanation:

area of a triangle is ½bh

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Help me pleeeeeeeeeeeeeeeease

pychu [463]

Answer:

n ≥ 29

She needs to do more than 29 pushups on the sixth day.

Step-by-step explanation:

First, we need to use the formula for finding the average. We currently have numbers for the first 5 days.

(22+26+21+25+27+n)/6 = 25

Multiply both sides by 6.

25*6 = 150

150-27-25-21-26-22=x

x=29

Since it is an inequality, Sarah needs to do more than 29 pushups on the sixth day.

6 0

2 years ago

WILL GIVE BRAINLYEST AND A LOT OF POINTS HELPPPPPP NOW Use the coordinate grid to determine the coordinates of point P:

oksian1 [2.3K]

Answer:

Step-by-step explanation:

next time take a deep breath

3 0

4 years ago

3a + 3b is equivalent to 3(a + 2b). A true B false

Sunny_sXe [5.5K]

Answer:

B-false

Step-by-step explanation:

It is false because where the 2 is, has to be 3, other wise it won't make sense. Because it will not equal the same thing.

4 0

3 years ago

Which number lies halfway between: a) 16 and 38 b) 259 and 361 1004 and 2 012?

xxTIMURxx [149]

Answer:

Which number lies halfway between:

a) 16 and 38 = 28

b) 259 and 361 =310

1004 and 2012?

=1058

8 0

3 years ago

How am I supposed to figure this out if csc Theta(0) has a radical number on the top?

Harman [31]

$\bf csc(\theta)=\cfrac{hypotenuse}{opposite}\implies csc(\theta)=\cfrac{\sqrt{7}}{2}\cfrac{\leftarrow hypotenuse=c}{\leftarrow opposite=b}\\\\
-----------------------------\\\\
\textit{so hmm using the pythagorean theorem, we can say that}\\\\
c^2=a^2+b^2\implies \pm \sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
b=opposite\\
a=adjacent
\end{cases}\\\\
\textit{we'll assume is the + of the root, since you're not}\\
\textit{given further info on it, that means the I quadrant}\\\\
$

$\bf -----------------------------\\\\
cos(\theta)=\cfrac{a}{c}\qquad sec(\theta)=\cfrac{c}{a}\qquad tan(\theta)=\cfrac{b}{a}\qquad cot(\theta)\cfrac{a}{b}
$

so just find the "adjacent" side, using the pythagorean theorem, and even though the square root can give you +/-, use the positive one, assuming the angle is in the 1st quadrant

keeping in mind, that the 2nd quadrant is feasible as well, since the opposite side of +2 can also be in the 2nd quadrant

but anyhow, use the I quadrant

7 0

3 years ago