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3 years ago

PLS HELP, WILL REWARD BRAINLIEST !!

Mathematics

2 answers:

Mrac [35]3 years ago

4 0

B is the answer to this

Alenkasestr [34]3 years ago

3 0

B is the answer trust

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What is the word phrase for 2x + 6

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3 years ago

I literally have a test tomorrow and dont know what to do please help

Fittoniya [83]

B is yes and the rest are no. B is the only solution where y equals 1.

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3 years ago

Read 2 more answers

Given the function f(x) = -2c+cx-x^2, and f^-1(5) = -1, find c

AnnZ [28]

Answer:

$c=-2$

Step-by-step explanation:

We are given the function:

$f(x) = -2c + cx - x^2$

And that:

$\displaystyle f^{-1} (5) = -1$

And we want to determine the value of <em>c</em>.

Recall that by definition of inverse functions:

$\displaystyle \text{If } f(a) = b, \text{ then } f^{-1}(b) = a$

So, since f⁻¹(5) = -1, then f(-1) = 5.

Substitute:

$f(-1) = 5 = -2c + c(-1) - (-1)^2$

Simplify:

$5 = -2c - c - (1)$

Combine like terms:

$6 = -3c$

And divide. Hence:

$c = -2$

In conclusion, the value of <em>c</em> is -2.

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3 years ago

Explain on the next slide how in 3 hours the car wouldn't travel 160 miles.

rosijanka [135]

Answer:

the car would have to be going under 5mph

Step-by-step explanation:

5 0

3 years ago

The rate of change (dP/dt), of the number of people on an ocean beach is modeled by a logistic differential equation. The maximu

Kazeer [188]

Answer:

$\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})$

Step-by-step explanation:

The logistic differential equation is as follows:

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

In this problem, we have that:

$K = 1200$ , which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.

At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.

This means that $\frac{dP}{dt} = 400$ when $P = 200$ . With this, we can find r, that is, the growth rate,

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

$400 = 200r(1 - \frac{200}{1200})$

$166.67r = 400$

$r = 2.4$

So the differential equation is:

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

$\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})$

3 0

3 years ago