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3 years ago

PLEASE HELPPPP

Mathematics

2 answers:

Elena-2011 [213]3 years ago

7 0

Answer:

T=40-3H

Step-by-step explanation:

Troyanec [42]3 years ago

5 0

Answer= T=40-3H

Explanation:

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Please help me with this thing please

Orlov [11]

98cm^2 is the area of the sector. Brainlist please

8 0

2 years ago

Problem page the longer leg of a right triangle is 1ft longer than the shorter leg. the hypotenuse is 9ft longer than the shorte

LenKa [72]

Hello,

To solve this problem we want to use the Pythagorean Theorem.
The pythagorean theorem states that for a 90° triangle,

$a^{2} + b^{2} = c^{2}$

where a and b represent the two legs of the triangle, and c represents the hypotenuse.

Let a = the longer leg and b = the shorter leg.
If the longer leg of the triangle is 1 foot longer than the shorter leg, then
a = b +1.

If the hypotenuse is 9 feet longer than the shorter leg, then c = b + 9.
Using the equations we created, we can plug them into the Pythagorean Theorem to solve for a, b, and c.

Doing this, we have:
$a^{2} + b^{2} = c^{2}$
$(b+1)^{2} + b = (b+9)^{2}$

Expanding this, we get $b^{2} + 2b + 1 + b^{2} = b^{2} + 18b + 81

 2b^{2} + 2b + 1 = b^{2} + 18b + 81

 b^{2} + 1 = 16b + 81

 b^{2} = 16b + 80
 
b^{2} - 16b - 80 = 0

$

Solving for b, we get b = 20, and b = -4.
The length of the side of a triangle cannot be negative, so we know that b = 20.

However, we should check this with the original question to make sure it checks out.

a = b + 1
a = 20 + 1 = 21

c = b + 9
c = 20 + 9 = 29

So, we have a = 21, b = 20, and c = 29. (Also, 20-21-29 is a well known Pythagorean triple)
Using the Pythagorean Theorem, we have:

$21^{2} + 20^{2} = 29^{2}$
441 + 400 = 841
841 = 841, checks out.

So, the shorter leg is 20 feet, the longer leg is 21 feet, and the hypotenuse is 29 feet.

Hope this helps!

7 0

3 years ago

Sienna used the scale drawing above to create a pool that is 14 ft wide x 22 ft long. She then decided to make pool with a final

Bond [772]

A scale factor allows a shape to be changes into another shape by changing the linear dimensions to the multiples of the initial dimension and a constant

The expression that finds the change in scale factor for the longer pool with a final length of 33 ft. Sierra is building is the option;

$\dfrac{2 \, ft.}{3 \, ft.}$

Reason:

Known parameters are;

Dimensions of the pool created = 14 ft. wide × 22 ft. long

Final length of the pool = 33 ft.

Let <em>x</em> represent the length of the drawing using the initial scale factor, we have;

$The \ initial \ scale \ factor = \dfrac{22 \, ft.}{x \, in.}$

The scale factor of the drawing following a final length of 33 ft. is therefore;

$New \ scale \ factor = \dfrac{33 \, ft.}{x \, in.}$

The change in scale factor is given as follows;

$Change \ in \ scale \ factor = \dfrac{Initial \, scale \, factor}{Final \, scale \, factor}$

Therefore;

$Change \ in \ scale \ factor = \frac{\left( \dfrac{22 \, ft.}{x \, in.} \right)}{\left( \dfrac{33 \, ft.}{x \, in.} \right)} = \dfrac{2 \, ft.}{3 \, ft.}$

Learn more here;

brainly.com/question/17637896

8 0

3 years ago

Read 2 more answers

Can someone please tell me the answer for this question.

8090 [49]

The answer to this question is the letter C:

-0.1*65 = -6.5
-6.5+110 + 103.5

4 0

3 years ago

In a random sample of 150 customers of a high-speed Internetprovider, 63 said that their service had been interrupted one ormore

erastovalidia [21]

Answer:

a) The 95% confidence interval would be given by (0.341;0.499)

b) The 99% confidence interval would be given by (0.316;0.524)

c) n=335

d)n=649

Step-by-step explanation:

1) Notation and definitions

$X_{IS}=63$ number of high speed internet users that had been interrupted one or more times in the past month.

$n=150$ random sample taken

$\hat p_{IS}=\frac{63}{150}=0.42$ estimated proportion of high speed internet users that had been interrupted one or more times in the past month.

$p_{IS}$ true population proportion of high speed internet users that had been interrupted one or more times in the past month.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

1) Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.42 - 1.96\sqrt{\frac{0.42(1-0.42)}{150}}=0.341$

$0.42 + 1.96\sqrt{\frac{0.42(1-0.42)}{150}}=0.499$

The 95% confidence interval would be given by (0.341;0.499)

2) Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: