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PolarNik [594]
3 years ago
13

Aye please help me with this math work

Mathematics
1 answer:
ipn [44]3 years ago
8 0
Where’s the math work?
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Solve 7(z +2) - 3z =44
maw [93]
7(z +2) - 3z =44
Distribute the 7. Distributive property: a(b+c) = ab + ac

7z + 14 - 3z = 44
Simplify like terms.

4z + 14 = 44
Subtract 14 to both sides

4z = 30
Divide by 4 on both sides.


z = 7.5
3 0
3 years ago
Read 2 more answers
Sylvia buys a case of water that contains 24 bottles and sells x number of bottles to her co-workers. Sam buys a case of water t
zzz [600]

Answer:

6

Step-by-step explanation:

Number of water bottles bought by Sylvia = 24

Number of water bottles sold by Sylvia = x

Number of water bottles left with Sylvia = 24-x

Number of water bottles bought by Sam = 36

Number of water bottles sold by Sam = Three times as many as bottles as Sylvia sold = 3x

Number of water bottles left with Sam = 36-3x

It is given that the number of water bottles left with Sylvia and Sam are equal.

i.e.

24-x=36-3x\\\Rightarrow 2x=12\\\Rightarrow x =\bold{6}

So, number of water bottles sold by Sylvia = <em>6</em>

7 0
3 years ago
How do i solve y=2x+5 y=3x-1 with substitutions dont know how to do this
marshall27 [118]

Answer:There is an app that helps you with this stuff.  

Step-by-step explanation:


4 0
4 years ago
There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0
4 years ago
A school assembly had 95 students in attendance, and 80% of them were first-graders. How many first-graders were at the assembly
Anettt [7]

Answer:

76

Step-by-step explanation:

If you multiply 95 by 0.8 (the percentage as a decimal), you get 76.

6 0
3 years ago
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