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Levart [38]
3 years ago
13

Find (fog)(x). f(x) = 2x

Mathematics
1 answer:
Blababa [14]3 years ago
3 0

Answer: (f•g)(x)=​2x²+12x

Step-by-step explanation:

(f•g)(x) is the same as saying f(x)•g(x). Since we have f(x) and g(x), we can just multiply them together.

(f•g)(x)=​2x(x+6)                [distribute by FOIL]

(f•g)(x)=​2x²+12x              

Now, we know that (f•g)(x)=​2x²+12x.

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Which situation is best represented by the following equation?
Gennadij [26K]

Answer:

D

Step-by-step explanation: because W in the equation is the number of weeks she paid for the self defense class. and the 12.50 would be the registration fee because that  is added on top of the number of 40w.

40w + 12.50 = 492.50

         -12.50       -12.50

40w = 480.00

w = 12 which is how many weeks she paid

5 0
3 years ago
Find the sum of 160,-125, and 40.
djyliett [7]

The answer is;

160 + (-125) + 40 = 75

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3 years ago
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Simplify each expression -5r (3r^2)​
Evgen [1.6K]

Answer:

The answer you're looking for is

-5r (3r^2) = -45

Step-by-step explanation:

7 0
4 years ago
When q = 15, r = 4<br> Find q when r = 7
djyliett [7]

Answer:

q = 18 ?

Step-by-step explanation:

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If we are following a pattern then we see q is 11 more than r.

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6 0
3 years ago
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The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO
Margarita [4]

Answer:

\angle PRQ = 80

Step-by-step explanation:

Given

\angle SPR = 145^o

\angle POT = 115^o

See attachment

Required

Find \angle PRO

First, calculate \angle RPO

\angle RPO + \angle SPR = 180 --- angle on a straight line

So, we have:

\angle RPO + 145 = 180

Collect like terms

\angle RPO = 180 - 145

\angle RPO = 35

Next, calculate PQR

\angle POR + \angle POT = 180

So, we have:

\angle POR + 115 = 180

Collect like terms

\angle POR = 180-115

\angle POR = 65

So, PRO is calculated as:

\angle PRO + \angle POR + \angle RPO = 180 --- angles in a triangle

So, we have:

\angle PRO + 65 + 35= 180

\angle PRO + 100= 180

Collect like terms

\angle PRO = 180-100

\angle PRO = 80

3 0
3 years ago
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