(05.03)

Mathematics

1 answer:

Maru [420]3 years ago

4 0

I believe second answer choice.

You might be interested in

1.3b^2 t 4b+1 when b=-2

lutik1710 [3]

1- 3(-2^2t)-7
2- 12+5=17
3- -10-6= -16
4- 2(-5^3)= -250

I can’t find the first one because of t

4 0

3 years ago

Find an for the arithmetic series with s16 = -288 And a1 =-21

Maru [420]

If $d$ is the common difference between terms in the sequence $\{a_n\}$ , then

$a_1=-21$
$a_2=a_1+d=-21+d$
$a_3=a_2+d=-21+2d$
...
$a_n=a_{n-1}+d=\cdots=-21+(n-1)d$

You're told that $S_{16}=-288$ (the sum of the first 16 terms in the sequence, presumably). Well, we know that

$S_{16}=\displaystyle\sum_{n=1}^{16}a_n=\sum_{n=1}^{16}(-21+(n-1)d)$
$S_{16}=\displaystyle(-21-d)\sum_{n=1}^{16}1+d\sum_{n=1}^{16}n$

Recall that

$\displaystyle\sum_{n=1}^kn=\frac{k(k+1)}2$

so that we have

$-288=16(-21-d)+\dfrac{16(16+1)}2d\implies d=\dfrac25$

So we get

$\begin{cases}a_1=-21\\\\a_n=-21+\dfrac25(n-1)\end{cases}$

8 0

3 years ago

Write the equation of the line in fully simplified slope-intercept form.

Nataliya [291]

Answer:

$y=-\frac{1}{4} x-6$

Step-by-step explanation:

The slope-intercept form is $y=mx+c$ , where m is the slope of the line and c is where the line crosses the $y$ -axis.

To calculate $m$ we can use the formula $m = \frac{dy}{dx}$ where $dy$ is the difference in $y$ between two points and $dx$ is the difference between $x$ .