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3 years ago

Plz help i am clueless

Mathematics

1 answer:

Ymorist [56]3 years ago

5 0

Answer:

-3 and 3 for your start on your y axis and it goes up 2 and right one

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1. How far does a car travel if it's 16-inch wheel rotates 3 times?<br><br><br>HELP!

Nataly_w [17]

$\textit{circumference of a circle}\\\\ C=\pi d~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=16 \end{cases}\implies C=16\pi \implies \stackrel{\textit{3 times that much}}{C=48\pi \implies} C\approx \underset{inches}{150.8}$

6 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

Lala how can you use a formula to find the perimeter of a polygon that has sides of equal length

goldfiish [28.3K]

if itis perimeter add all sides

if it is área multiply

4 0

3 years ago

4/50 converted into a percentage

Arlecino [84]

Answer:

Step-by-step explanation:

$\frac{4}{50}*100=4*2$

= 8%

3 0

3 years ago

Joe has to take two quizzes tomorrow. He has only enough time to study for one of them. The science quiz has 6 true or false que

finlep [7]

Answer:

C) English

Step-by-step explanation:

I don't really know how to explain it, so I'll show you instead.

For science, there are 6 of 6 correct answers with a 0.5 chance of answering correctly.

So,

0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5 = 0.016

For English, there are 4 of 4 correct answers with a 0.25 chance of answering correctly.

So,

0.25 x 0.25 x 0.25 x 0.25 = 0.004

They will have to study English (0.004) because it is lower than science (0.016).

4 0

3 years ago

Read 2 more answers

Plz help i am clueless ​

Plz help i am clueless