All categories

3 years ago

True or false? linear pairs of angles are congruent

Mathematics

2 answers:

guapka [62]3 years ago

8 0

False. linear pair are always supplementary , which means their measures add up to 180° .

charle [14.2K]3 years ago

4 0

Answer:

true

Step-by-step explanation:

You might be interested in

WILL GIVE BRAINLIEST IF YOUR RIGHT!!!!

Crazy boy [7]

Answer:

I.I

R.R

Step-by-step explanation:

R.R would be R.RRRR......

and I.I would be I.IIII...

5 0

3 years ago

Read 2 more answers

A new restaurant is attracting customers with searchlights has a radius of 2 feet. What is the searchlights circumference?

Assoli18 [71]

Answer:

12.56 feet

Step-by-step explanation:

The perimeter of a shape is the sum of all its side.

Since circle doesn't have "sides", the perimeter is the length of the whole circle. This has the name "circumference".

The circumference of a circle has the formula:

$C=2\pi r$

Where

C is the circumference (perimeter of a circle)

r is the radius

Given,

r = 2 feet

We substitute and find the circumference, using 3.14 as $\pi$ ,

$C=2\pi r\\C=2(3.14) (2)\\C=12.56$

Hence, the circumference is 12.56 feet

5 0

3 years ago

Can someone help me with this please

ryzh [129]

Answer:

y=4

Step-by-step explanation:

You can ignore the 3 and 6 because this has no y value change(rise over run)

This is a straight horizontal line so the equation is y=4.

Slope=0

4 0

2 years ago

A sphere of radius r is cut by a plane h units above the equator, where

Anika [276]

Consider the top half of a sphere centered at the origin with radius $r$ , which can be described by the equation

$z=\sqrt{r^2-x^2-y^2}$

and consider a plane

$z=h$

with $0$ . Call the region between the two surfaces $R$ . The volume of $R$ is given by the triple integral

$\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$

Converting to polar coordinates will help make this computation easier. Set

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

Now, the volume can be computed with the integral

$\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

You should get

$\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)$

5 0

3 years ago

Solve for the variable: 12 = 5x = 7

IrinaVladis [17]

Hello from MrBillDoesMath!

Answer: x = 1

Discussion :

Per the author, the equation to solve is 12 = 5x + 7

Isolate the "x" variable by subtracting 7 from both sides of the equation:

12 = 5x + 7

-7 = -7

---------------------

12-7 = 5x + 0

5 = 5x

Dividing both sides by 5 gives x - 1

Regards, MrB

6 0

3 years ago