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3 years ago

Given vectors a = <9, 9> and b = <–4, 7>, find 3a − 2b.

Mathematics

1 answer:

dmitriy555 [2]3 years ago

7 0

Answer:

35i+13j

Step-by-step explanation:

Vector a = 9i+9j

Vector b = -4i+7j

We need to find the value of 3a-2b.

3a = 3(9i+9j) = 27i+27j

2b = 2(-4i+7j) = -8i+14j

3a-2b = 27i+27j-(-8i+14j)

= 27i+27j+8i-14j

= 35i+13j

Hence, the required vector is equal to 35i+13j.

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I’m stuck please help

Katena32 [7]

Answer:

Step-by-step explanation:

8 0

3 years ago

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The tempeture of chicken soup is 192.7 degrees F. As it cools the tempeture of the soup decreases 2.3F per minute.

IrinaK [193]

Answer:

Step-by-step explanation:

To find the answer to Part A, we can turn this into a simple equation:

192.7 - (2.3 times 25) = temperature, the missing value.

So therefore, after 25 minutes pass, the temperature is equal to

192.7 - 57.5, or:

135.2 = Answer to Part A.

Now, onto Part B. We can use another equation!

192.7 - 2.3x = 100.7

Now, we must solve the given equation, first by taking 100.7 from each side:

192.7 - 2.3x = 100.7

-100.7 -100.7

We are now left with: 92 - 2.3x = 0 - we must now add 2.3x to 2.3x and 0, giving us this:

92 = 2.3x, which is equivalent to 920 = 23x, if that is what you prefer to solve.

To give us our missing value (x), we can divide 920 by 23, giving us: x = 40. This is the answer to Part B: 40 minutes.

I hope this was really helpful! Tell me if you need any more help.

6 0

2 years ago

In the function y=5x^2-2, what effect does the number 5 have on the graph, as compared to the graph of y=x^2?

allochka39001 [22]

General Idea:

The Rules for Transformations of Functions are given below:

If f(x) is the original function, a > 0 and c > 0; Then

$f(x)+k \; \; shift \; f(x) \; UPWARD \; k \; units\\\\f(x)-k \; \; shift \; f(x) \; DOWNWARD \; k \; units\\\\f(x+h) \; \; shift \; f(x) \; LEFT \; h \; units\\\\f(x-h) \; \; shift \; f(x) \; RIGHT \; h \; units\\\\-f(x) \; \; REFLECT \; f(x) \; in \; the \; x-axis\\\\f(-x) \; REFLECT \; f(x) \; in \; the \; y-axis\\\\a \cdot f(x), \; a>1 \; STRETCH \; f(x) \; vertically \; by \; a \; factor \; of \; a\\\\a \cdot f(x), \; 0$

$f(ax), \; a>1 \; SHRINK \; f(x) \; horizontally \; by \; a \; factor \; of \;\frac{1}{a} .\\\\f(ax), \; 0$

Applying the concept:

In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:

C.it stretches the graph vertically by a factor of 5

4 0

4 years ago

Read 2 more answers

Find the domain and range of the relation. Also determine whether the relation is a function.

OLEGan [10]

Answer:

The relation is a function!

Your Domain should be...

{-1, 1, 7, 9}

Your Range should be...

{-1, 8, 9}

WHY?

Your domain is always your x-coordinates, which are the first coordinates in a pair.

Your range is always your y-coordinates, which are the second coordinates in a pair.

When listing the points, it's important to remain a relation CANNOT be a function if the x's repeat, so luckily, they do not repeat.

Also, when listing points for your range, remember, if they repeat, you should only count one of the numbers, as you can see from the answer, there was two nines, but instead I put one.

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3 years ago

$30,000 is invested for 15 years with an APR of 4.5% and daily compounding.

Alex73 [517]

Answer:

202500

Step-by-step explanation:

15x0.45=6.75

30000x6.75=202500

6 0

2 years ago