Question

y=f(x) is odd (f(-x)=-f(x)) and f(x>0) = x^2-5x-12, x is not = to 0. What points does the line f(x)=12 go through.

Answer 1

f(x<0)=-f(x>0)=-x^2+5x+12 When x>0, x^2-5x-12=12, x=8, y=12 Therefore, f(x)=12 goes through point (8,12).