You can rule out A and C 6/6 makes 1 so that cancels so your answer is D
Answer:
77%
Step-by-step explanation:
Given the following :
Probability of winning both games = 50%
Probability of winning just the first game = 65%
Let the probability of winning the ;
First game = p(A) = 65%
Second game = p(B)
Both games = p(A and B) = 50%
What is the probability that the team will win the 2nd game given that they have already won the first game
The above question is a conditional probability question :
Probability of winning the second Given that they've already won the first = p(B | A)
p(B | A) = (A and B) / p(A)
p(B | A) = 50% / 65%
p(B | A) = 0.5 / 0.65
p(B | A) = 0.7692307
= 76.9% = 77%
When two people respond you press the crown next to the best answer which marks it brainliest
Answer:
Step-by-step explanation:
The Two triangles are Similar, so using the property of the similar triangles.
On cross multiplication of the fraction:
Dividing by '10' both the sides:
So, the side(m) of the small triangle is '6'
Answer:
C) x^2 + y^2 = 16
Step-by-step explanation:
<h2><u>Find the equation </u></h2>
since the radius is 4 this means that anywhere from the center of the circle to the edge of the circle is 4. hence :
place the horizontal line of the radius where y = 0 .
this means that if y = 0 , then x = 4
therefore :
x^2 + y^2
4^2 + 0^2
= 16
<h3><u>hence the answer is C ) x^2 + y^2 = 16</u></h3>