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AveGali [126]
2 years ago
15

What is the area of the figure below?

Mathematics
1 answer:
Cerrena [4.2K]2 years ago
6 0
A=(a+b/2) x h

a = 8
b = 14
h = 14

(8+14/2) x 14

(22/2) x 14

11 x 14 = 154

The answer is 154
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Step-by-step explanation:

the answer is

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2 years ago
I’m kinda confused. Can someone help.
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Answer:

PQ = PM\cos MPQ + MQ\cos MQP=2PM\cos MQP

Step-by-step explanation:

given MQR = 60, PQR = 75

MQP = 75 -60= 15QR = ((18(1+\cos 30))^{2}-(2\cos 15)^{2})^{\frac{1}{2}}

WE KNOW THAT MQR +QRM +QMR = 180

MPQ = MQP AS ANGLE OPPOSITE TO EQUAL SIDES ARE EQUAL

THEREFORE QMR = 90 - 60 = 30

therefore PQM = 75 - 60 = 15

PM = PQ because M is the mid point

therefore PR = PM + MQ\cos QMR

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QR = (PR^{2}-PQ^{2}))^{\frac{1}{2}}

PQ = PM\cos MPQ + MQ\cos MQP=2PM\cos MQP

5 0
3 years ago
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lesya692 [45]

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Step-by-step explanation:

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2 years ago
Which of the following would be considered a monomial? Select all that apply
Vaselesa [24]

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The problem cannot be fully solved because you did provide the line on which the line is parallel/ but i can give you the steps on how to solve it. first solve the slope of the parallel line by
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5 0
3 years ago
Read 2 more answers
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