Area of a triangle is given by 1/2bh where b is the base and h is the perpendicular height of the triangle.
The area is 80x∧5y³ and the height is x∧4y
Thus; 80x∧5y³ = 1/2(x∧4y) b
160x∧5y³ = (x∧4y)b
b = (160x∧5y³)/ x∧4y)
b = 160xy²
Therefore, the base of the triangle is 160xy²
Answer:
x:-4,-3,-2,-1,0,1
f(x):-10,0,0,-4,-6,0
from the table we can see when x=0, y=-6
Therefore the y-intercept will be (0,-6)
<u>OAmalOHopeO</u>
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We can see that the graph touches 
without crossing the x-axis (i.e. it is a double solution), and then there's another zero at 
(this time it's a crossing zero, so a single solution).
This leads, up to multiple, to the polynomial
If we impose the passing through 
we have
So, the polynomial is
Finally, to solve 
, simply look at the graph, searching for the points, where the graph is below the x-axis. You can see that this happens only if 
, so that's the solution to your question.
D. positive linear relationship
