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3 years ago

11

A college basketball player makes 80% of his free throws. Over the course of the season he will attempt 100 free throws. Assumin

g free throw attempts are independent, what is the probability that he makes at least 80 of these attempts?

1 answer:

Sedaia [141]3 years ago

7 0

Answer:I think its .008

Step-by-step explanation:

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5. Solve. 1/2 p +9/ 4 = 7 / 4

Papessa [141]

Answer:P=-1

Step-by-step explanation:

1/2-1+9/4=7/4

4 0

3 years ago

Talja [164]

Answer:

13 and 27

Step-by-step explanation:

y= x+14

x+y=40

x+ x+14=40

2x+14=40

40-14=26

so, 2x=26

26/2

=13

so, x=13 and

and y equal 40-13

y=27

3 0

2 years ago

Vesnalui [34]

Try 1(18) / 2

Just multiply 1 by 18 and divide 18 by 2.
Then we have 9!

8 0

2 years ago

What is the answer to the question -6=n+5n

iVinArrow [24]

Answer:

-1=n I believe would be the answer.

4 0

3 years ago

10 points!!! please help :(

daser333 [38]

To complete the identity, we need these fundamental identities:

$1)\displaystyle{sec(x)=\frac{1}{cos(x)}$

$2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)$

$\displaystyle{csc(x)= \frac{1}{sin(x)}$

Thus, by identity 1 we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}$

by identity :

$\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)$

recall the values :

$\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\$

$\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0$ ,

so:

$cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)$

Putting all these together, we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}$

which is equal to $csc(\theta)$ , by identity 3

Answer: D

7 0

3 years ago