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tresset_1 [31]
3 years ago
9

50 POINTS NEED HELP1. Does the table represent y as a function of x? Justify your answer​

Mathematics
2 answers:
FromTheMoon [43]3 years ago
6 0

yes it look like it does so yeah bbbbyyyyeeeee

olga2289 [7]3 years ago
4 0

Answer: no.

Step-by-step explanation: There isnt a consistent pattern or equation between x and why, so the y variables are not functions of x.

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5 cups to 8 cups <br> identify the percent
Kipish [7]
Well I am going to guess and i don't know if it right but 156.25ml
5 0
3 years ago
for the equation 2x(3x+5)+3(3x+5)=ax^2+bx+c , if this equation is true for all values of x,what is the value of b if a,b,and c a
guapka [62]

Answer:

b=19

Step-by-step explanation:

2x(3x+5)+3(3x+5)=ax2 +bx+c

by expansion,

6x2 +10x +9x+15=6x2 +19x +15

6 0
3 years ago
How to solve 3y+6=5y-18
MariettaO [177]

Answer:

y = 14

Step-by-step explanation:

move 5y over to the left and you should get -2y +6=-18. subtract 6from both sides and you will now have -2y=-24. divide bothe sides from -2 and you will get y=14

4 0
4 years ago
Read 2 more answers
The area of the closet floor is 18 feet. If Saroya buys 32 tiles will she have enough to cover the floor?
kvasek [131]
No shel will not have enough tile.  If you don't know the dimensions of the actual tile how will you solve.  If you have a closet 18 square feet it could be 9 ' x 2 ' = 18 square feet. If the tiles were 12" x 6" you would need 36 tiles.  If the closet was 6' x 3' = 18 square feet you could have the tiles 12" x 6" = 36 tiles.  So you need to know the dimensions of the tile.
4 0
3 years ago
Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

8 0
3 years ago
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