Answer:
50%
Step-by-step explanation:
Let the total number of trees be T and suppose that this is made up of eucalyptus trees E and other kinds of trees, O.
Then E+O=T, and since 99% of the trees are eucalyptus trees, EE+O=0.99.
Therefore
0.99E+0.99O=E
0.01E=0.99O
E=99O.
Suppose we reduce the number of eucalyptus trees by some amount x and that the remaining number of eucalyptus trees are now 98% of the total trees.
Then we would have E−x(E−x)+O=0.98.
Therefore,
0.02(E−x)=0.98O
0.02E−0.02x=0.98O
0.02x=0.02E−0.98O
x=E−50(0.98)O
x=E−49O
x=E−49(E99)
x=5099E≈0.505050...×E.
So we end up removing a little over half of the eucalyptus trees. EDIT: Forgot to mention - removing 50.505050...% of the eucalyptus trees means that we are removing 0.50505050....×0.99T which is 0.5T or half the trees in the neighborhood.
9514 1404 393
Answer:
A. Simon's unit rate is 2 more miles per hour than Eric's unit rate
Step-by-step explanation:
We are concerned with the number of miles each runs in 1 hour.
For Eric, that means x=1 in his equation, so his mileage is ...
y = 6×1 = 6 . . . . miles
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For Simon, it means we want to find time = 1 hour on the horizontal axis at the bottom of the graph. Then we want to see where the graphed line crosses that vertical line. The point of crossing has horizontal line that goes over to 8 on the vertical distance axis. That is, Simon runs 8 miles in 1 hour.
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Eric's unit rate (miles in 1 hour) is 6 miles per hour.
Simon's unit rate (miles in 1 hour) is 8 miles per hour.
Simon's unit rate is 2 more miles per hour than Eric's unit rate.
3.78 x 10^9 = 3780000000 = 3,780,000,000
3,780,000,000 / 14,000 = 270,000
270,000 = 2.7 x 10^5
Answer: Point D
Step-by-step explanation:
92 is in between 81 and 100, so 
Answer:
look at the picture i have sent
