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Zielflug [23.3K]
3 years ago
13

Duncan foods orders 500 cans of crushed tomatoes every month to be consistent with recommendations made by the EOQ model. If the

annual inventory holding cost is​ $0.50 per can per​ year, then what are its annual inventory holding costs in​ dollars? (assume that the assumptions for the EOQ model​ hold) nothing
Business
1 answer:
Pie3 years ago
7 0

Answer:

$125

Explanation:

average inventory = 500 / 2 = 250

annual holding costs = 250 x $0.50 = $125

also, if you want to determine the order cost:

EOQ = √[(2 x S x D) / H]

EOQ = 500

H = annual inventory holding cost per unit = $0.50

D = annual demand = 500 x 12 = 6,000

500 = √[(2 x S x 6,000) / 0.50]

500² = 12,000S / 0.50

250,000 x 0.5 = 12,000S

125,000 = 12,000S

S = 125,000 / 12,000 = $10.417 ≈ $10.42

annual ordering costs = $10.42 x 12 = $125.04

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An organization that offer goods and services to customers to earn a profit are known as, for profit organizations. A for profit organization is a organization that has a goal to earn profit from their customers.

7 0
3 years ago
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Leadership in small firms is more ____ in comparison to the leadership in large corporations.
enyata [817]

Answer:

different

Explanation:

There is  a significant difference in small firms leadership compared to large firms depending on legal structures, number of employees in a firm and financial availability.

Large firms have more departments, employees, and operations compared to small ones. For instance, the leadership style and structure required to manage operations and employees in large firms will need to be highly structured to ensure there is effective  command and information flow. For small firms, a simple command and communication flow structure will suffice as the number of employees and departments involved are few.

8 0
3 years ago
Amber Corporation donated inventory of clothing (basis of $136,000, fair market value of $170,000) to a qualified charitable org
viva [34]

Answer:

charitable contribution deduction =  $153000

Explanation:

given data

basis = $136,000

fair market value = $170,000

solution

we get here charitable contribution deduction that is express as

charitable contribution deduction = Basis + 50% of (Fair - basis)    .......................1

put here value and we get

charitable contribution deduction = $136,000 + 0.50 ($170,000 - $136,000 )

charitable contribution deduction =  $153000

3 0
3 years ago
A machine costing $251,800 was purchased May 1. The machine should be obsolete after three years and, therefore, no longer usefu
e-lub [12.9K]

Answer:

Instructions are listed below.

Explanation:

Giving the following information:

A machine costing $251,800 was purchased May 1. The machine should be obsolete after three years and, therefore, no longer useful to the company. The estimated salvage value is $3,400.

A) Straight-line:

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= (251,800 - 3,400)/3= $82,800

B) Double declining balance:

Annual depreciation= 2*[(original cost - residual value)/estimated life (years)]

Year 1= (248,400/3)*2= 165,600

Year 2= 55,200

Year 3= 18,400

5 0
3 years ago
Let $S$ be the set of complex numbers of the form $a + bi,$ where $a$ and $b$ are integers. We say that $z \in S$ is a unit if t
lakkis [162]

Answer:

Number of units possible in S are 4.

Explanation:

Given <em>S</em> is a set of complex number of the form a+bi where <em>a</em> and <em>b</em> are integers.

z\in S is a unit if w\in z exists such that zw=1.

To find:

Number of units possible = ?

Solution:

Given that:

zw = 1

Taking modulus both sides:

|zw| = |1|

Using the property that modulus of product of two complex numbers is equal to their individual modulus multiplied.

i.e.

|z_1z_2|=|z_1|.|z_2|

So,

|zw| = |1|\\\Rightarrow |zw| =|z|.|w| =1\\\Rightarrow |z|=\dfrac{1}{|w|}......... (1)

Let z=a+bi

Then modulus of z is   |z| = \sqrt{a^2+b^2}

Given that a and b are <em>integers</em>, so the equation (1) can be true only when |z| = |w| =1 (Reciprocal of 1 is 1). Modulus can be equal only when one of the following is satisfied:

(a = 1, b = 0) ,  (a = -1, b = 0), (a = 0, b = 1) OR (a = 0, b = -1)

So, the possible complex numbers can be:

1.\ 1 + 0i = 1\\2.\ -1 + 0i = -1\\3.\ 0+ 1i = i\\4.\ 0 -1i = -i

Hence, number of units possible in S are 4.

6 0
3 years ago
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