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trasher [3.6K]
3 years ago
13

Kevin measured a line to be 12.4 inches long. If the actual length of the line is 15.7 inches, then what was the percent error o

f the measurement, to the nearest tenth of a percent?
Mathematics
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

The percent error of the measurement, to the nearest tenth of a percent is 21.0\%

Step-by-step explanation:

Estimated length of a line = 12.4 inches

Actual length of the line = 15.7 inches

Error = 15.7 - 12.4 = 3.3 inches

Percent error of the measurement =\frac{3.3}{15.7}(100)=21.02 ≈ 21.0

So, the percent error of the measurement, to the nearest tenth of a percent is 21.0\%

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50 POINTS!! HELP!
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y1 is the y point you are given

x1 is the x point you are given

m is your slope

substitute all of those in from the question

the first one is:

y --4 = -5/6(x-8)

-- turns into a plus so the answer would be

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6 0
2 years ago
What is the area of a rectangle that is 1 1/4 m long and 3/4 of a meter wide
Marat540 [252]

Answer:

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2 years ago
Evaluate the log by thinking “3 to what power is 1/9 so log3(1/9) =
Vlad [161]

Answer:-2

Step-by-step explanation:

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Log(1/9) ➗ Log3

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3 years ago
Write the equation of the line that passes through (0, 3) and is parallel to the line 3x + 5y = 6.
Pavel [41]
Please, see the offered decision:
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2) for line 3x+5y=6   k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5).
3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b:
3=0*(-3/5)+b ⇔ b=3.
4) finaly (k=-3/5; b=3):
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3 0
2 years ago
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