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Fantom [35]
3 years ago
11

Can someone help me with this??

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

here you go

Step-by-step explanation:

18 is 24c/d^5

19 is 48a^/b^3

/ indicates a fraction

^ indicates an exponent

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Write an equation in​ point-slope form of the line that passes through the given​ points, then write the equation in​ slope-inte
frosja888 [35]

As we go from (-6,6) to (9,1), x increases by 15 and y decreases by 5.  Thus, the slope of this line is m = rise / run = -5/15, or m = -1/3.

Point-slope form:  y-6 = (-1/3)(x+6), using data from (-6,6).  

Slope-intercept form:  starting with y = mx + b, substit. -6 for x, 6 for y and -1/3 for m:

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6 = 2 + b.  Then b = 4, and the equation in slope-intercept form is

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3 years ago
Need help with #1 #4 #7 plz giving 15 points
valentina_108 [34]

Answer:

Q1:  p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{8} \hspace{1mm}  \textbf{=} \hspace{1mm} \textbf{3}

We solve this taking LCM.

We get: $ \frac{-p - 24}{3} = 3 $

$ \implies - p - 24 = 9 $

$ \implies \textbf{p} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 33} $

Q4: $ \frac{\textbf{d}}{\textbf{11}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{4} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Again we proceed like Q1 by taking LCM.

We get: $ \frac{d - 44}{11} = - 13 $

$ \implies d - 44 = - 13 \times 11 = - 143 $

$ \implies d = - 143 + 44 $

$ \implies \textbf{d} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 99} $

Q7: 5t + 12 = 4t - 1

We club the like terms on either side.

$ \implies 5t - 4t = - 1 - 12 $

$ \implies (5 -4)t = - 13 $

$ \implies \textbf{t} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Hence, the answer.

7 0
3 years ago
A square field has a perimeter of 48cm find the area of the field​
BabaBlast [244]

Answer:

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Step-by-step explanation:

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