Answer:
The answer to your question is csc Ф = 
Step-by-step explanation:
Process
1.- Determine the sign
We must determine csc Ф in the forth quadrangle, here csc is negative.
2.- Determine the hypotenuse
c² = a² + b²
c² = 3² + (-4)²
c² = 9 + 16
c² = 25
c = 5
3.- Determine csc Ф
csc Ф = 
csc Ф =
= 
Answer:
cos
(
5
π
12
)
=
√
2
−
√
3
2
Explanation:
By the half angle formula:
XXXX
cos
(
θ
2
)
=
±
√
1
+
cos
(
θ
)
2
If
θ
2
=
5
π
12
XXXX
then
θ
=
5
π
6
Note that
5
π
6
is a standard angle in quadrant 2 with a reference angle of
π
6
so
cos
(
5
π
6
)
=
−
cos
(
π
6
)
=
−
√
3
2
Therefore
XXXX
cos
(
5
π
12
)
=
±
⎷
1
−
√
3
2
2
XXXXXXXXXXX
=
±
⎷
2
−
√
3
2
2
XXXXXXXXXXX
=
±
√
2
−
√
3
4
XXXXXXXXXXX
=
±
√
2
−
√
3
2
Since
5
π
12
<
π
2
XXXX
5
π
12
is in quadrant 1
XXXX
→
cos
(
5
π
12
)
is positive
XXXX
XXXX
XXXX
(the negative solution is extraneous)
answer in pic more explain
Answer:
40 days saw either rain or high winds
Step-by-step explanation:
We solve this question using Venn sets.
I am going to say that:
Set A: Rain
Set B: High winds.
18 days saw rain
This means that 
29 days saw high winds
This means that 
7 days saw both rain and high winds.
This means that 
How many days saw either rain or high winds?
This is

Sp

40 days saw either rain or high winds