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san4es73 [151]
3 years ago
12

When a balloon is blown up then let go air molecules rush out of the balloon and join the air molecules in earths atmosphere wha

t happens to the enthalpy in the balloon?

Chemistry
2 answers:
damaskus [11]3 years ago
7 0

Answer: It decreases.

Explanation: a p e x :)

salantis [7]3 years ago
6 0

Answer: It decreases

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4FeS2 + 11O2 > 2Fe2O3 + 8SO2
BartSMP [9]

Answer:

80.13g of SO2

Explanation:

4FeS2 + 11O2 —> 2Fe2O3 + 8SO2

Molar Mass of FeS2 = 55.8 + (2x32) = 119.8g/mol

Mass of FeS2 from the balanced equation = 4 x 119.8 = 479.2

Molar Mass of SO2 = 32 + (16x2) = 32 + 32 = 64g/mol

Mass of SO2 from the balanced equation = 8 x 64 = 512g

From the equation,

479.2g of FeS2 produced 512g of SO2.

Therefore, 75g of FeS2 will produce = (75 x 512)/479.2 = 80.13g of SO2

3 0
4 years ago
Which statement best describes the formula equation ci2(g)+2kbr(aq)-2kci(aq)+ Br2(i)
BARSIC [14]

The statement that describes the chemical reaction is D chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromide. The symbol "Cl" represents chlorine. The symbols in the brackets show the physical state of the substance, (g) is gaseous, (s) is solid, (aq) is aqueous and (l) is liquid.

6 0
4 years ago
Which provides evidence to support the big bang theory?
Stolb23 [73]
A<span>. </span>
<span>the change in carbon dioxide levels in the atmosphere 
</span>
hope that's right and hope i helped




6 0
3 years ago
What is true about energy in an ordinary chemical reaction? Energy is
RSB [31]
Energy is not created or destroyed due to the law of Conservation of Energy. Hope this helps!
3 0
3 years ago
Read 2 more answers
For the simple decomposition reactionAB(g)→ A(g) + B(g)Rate =k[AB]2 and k=0.2 L/mol*s . How long will it takefor [AB] to reach 1
mixer [17]

Answer:

6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.

Explanation:

Rate = k[AB]^2

The order of the reaction is 2.

Integrated rate law for second order kinetic is:

\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt

Where, [A_0] is the initial concentration  = 1.50 mol/L

[A_t] is the final concentration  = 1/3 of initial concentration = \frac{1}{3}\times 1.50\ mol/L = 0.5 mol/L

Rate constant, k = 0.2 L/mol*s

Applying in the above equation as:-

\frac{1}{0.5} = \frac{1}{1.50}+0.2t

\frac{1}{1.5}+0.2x=\frac{1}{0.5}

t = 6.66\ s

<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>

5 0
3 years ago
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