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olga_2 [115]
4 years ago
13

What volume of 0.147 molar sulfuric acid solution would be required to neutralize completely 36 ml of 0.466 molar sodium hydroxi

de solution?

Chemistry
1 answer:
Lapatulllka [165]4 years ago
4 0
Hope this helps:):);)

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The specific heat of water is 4.18 J/(g⋅∘<br> c. Calculate the molar heat capacity of water.
Xelga [282]

We are given that the specific heat of water is 4.18 J / g °C. We know that the molar mass of water is 18.02 g/mol, therefore the molar heat capacity is:

 

molar heat capacity = (4.18 J / g °C) * 18.02 g / mol

<span>molar heat capacity = 75.32 J / mol °C</span>

6 0
3 years ago
Read 2 more answers
What is the poH of a<br> 2.6 x 10-6 M H+ solution?<br> pOH = [?]
KatRina [158]

Answer:

pOH = 8.41

Explanation:

From the question given above, we obtained the following information:

Concentration of Hydrogen ion [H⁺] = 2.6×10¯⁶ M

pOH =?

Next, we shall determine the pH of the solution. This can be obtained as follow:

Concentration of Hydrogen ion [H⁺] = 2.6×10¯⁶ M

pH =?

pH = – Log [H⁺]

pH = – Log (2.6×10¯⁶)

pH = 5.59

Finally, we shall determine the pOH of the solution. This can be obtained as follow:

pH = 5.59

pOH =?

pH + pOH = 14

5.59 + pOH = 14

Collect like terms

pOH = 14 – 5.59

pOH = 8.41

Therefore, the pOH of the solution is 8.41

5 0
3 years ago
Read 2 more answers
to checkt the accuracy of a new method, a standard copper alloy containing 23.24%Cu was analyzed and calculated to contain 23.17
tekilochka [14]

Answer:

23.24%_23.17%

10%×1000

10/100×1000=

100

3 0
3 years ago
Does iodine occur naturally in salt ? yes or no​
dangina [55]

Answer:

yes

Explanation:

Iodine is present in salt which makes it salty:)

6 0
3 years ago
__Na3PO4 + __Sr(NO3)2 --&gt; ___Sr3(PO4)2 + __NaNO3
lisov135 [29]

Answer:

0.0526mol

Explanation:

The chemical equation given in this equation is as follows:

Na3PO4 + Sr(NO3)2 → Sr3(PO4)2 + NaNO3

However, this equation is unbalanced as the number of atoms of each element on each side does not correlate. The balanced equation is as follows:

2Na3PO4 + 3Sr(NO3)2 → Sr3(PO4)2 + 6NaNO3

This balanced equation means that:

2 moles of Sodium Phosphate (Na3PO4) is required to react with 3 moles of Strontium Nitrate (Sr(NO3)2)

Hence, if 0.0789 moles of Strontium Nitrate are reacted, then 0.0789 × 2/3

moles of sodium phosphate will also react.

= 0.0789 × 2/3

= 0.1578/3

= 0.0526mol

5 0
3 years ago
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