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olga_2 [115]
4 years ago
13

What volume of 0.147 molar sulfuric acid solution would be required to neutralize completely 36 ml of 0.466 molar sodium hydroxi

de solution?

Chemistry
1 answer:
Lapatulllka [165]4 years ago
4 0
Hope this helps:):);)

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Can you please explain why the metal doesn't rust at b
Anna71 [15]

(a)  (i) Zinc blende is mainly Zinc sulphide and in industry it is converted to ZnO by flames to burn off the sulphur as SO2 which is then used to make sulphuric acid.

(ii)   Reduction of ZnO to Zn:-

2ZnO + C = CO2 + 2Zn

(b) This is called sacrificial anodic protection.  The zinc ( which is more reactive than iron) when in contact with the oxygen in the air is oxidised and in the process loses its electrons. These travel  through the electrolyte to the iron. The electrons then reduce any iron oxide to iron: fe2+ + 2e  ---> Fe.


7 0
3 years ago
What is the total number of hydrogen atoms in a molecule of heptyne?
Step2247 [10]

Answer:

12

Explanation:

alkyne formula is CnH2n-2

heptyne = 7

6 0
3 years ago
If nitrogen and hydrogen combine in a synthesis reaction, what would the product of the reaction be? n2 + 3h2 → 3
Fed [463]
N2 + 3H2 ---> 2NH3
nitrogen + hydrogen ---> ammonia
4 0
3 years ago
Read 2 more answers
How many moles are in 213 grams of NaCl?
Nata [24]

Answer:

There are 3, 64 moles of NaCl.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate themoles in 213 grams of NaCl, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl = 23 g + 35, 5 g= 58, 5 g/ mol

58,5 g ------1 mol NaCl

213 g---------x= (213 g x 1 mol NaCl)/ 58, 5 g= <em>3, 64 mol NaCl</em>

5 0
4 years ago
How much heat is released as the temperature of 25.2 grams of iron is decreased from 72.1°C to 9.8°C? The specific heat of iron
prisoha [69]

Answer:

Q=-697.06\ J

Negative sign says that release of heat.

Explanation:

The expression for the calculation of the heat released or absorbed of a process is shown below as:-

Q=m\times C\times \Delta T

Where,  

\Delta H  is the heat released or absorbed

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass = 25.2 g

Specific heat = 0.444 J/g°C

\Delta T=9.8-72.1\ ^0C=-62.3\ ^0C

So,  

Q=25.2\times 0.444\times -62.3\ J=-697.06\ J

Negative sign says that release of heat.

8 0
3 years ago
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